You are conducting a test of homogeneity for the claim that two different populations have the same proportions of the following two characteristics. Here is the sample data. Category Population Population $2 70 28 #1 61 19 The expected observations for this table would be Population #2 Population Category #1 58.876 72. 124 A 21.124 of 25.876 The resulting Pearson residuals are: Category Population Population #1 #2 A 077 063 214 174

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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You are conducting a test of homogeneity for the claim that two different populations have the
same proportions of the following two characteristics. Here is the sample data.
Population Population
#1
Category
# 2
A
61
70
B
19
28
The expected observations for this table would be
Population
Population
Category
#1
#2
58.876
o 72. 124
A
B
21.124
25.876
The resulting Pearson residuals are:
Population
Population
Category
# 1
#2
A
.077
063
214
174
You are conducting a test of independence for the claim that there is an association between the
row variable and the column variable.
x Y Z
A 31 34 4
B 26 43 5
The expected observations for this table would be
Y.
A 27 503 vo || 37. 154
4 343
B
29 497 o
39.846 o
4.657
The resulting Pearson residuals are:
Y
A
445
of
268
027
B
415
250
.025
Transcribed Image Text:You are conducting a test of homogeneity for the claim that two different populations have the same proportions of the following two characteristics. Here is the sample data. Population Population #1 Category # 2 A 61 70 B 19 28 The expected observations for this table would be Population Population Category #1 #2 58.876 o 72. 124 A B 21.124 25.876 The resulting Pearson residuals are: Population Population Category # 1 #2 A .077 063 214 174 You are conducting a test of independence for the claim that there is an association between the row variable and the column variable. x Y Z A 31 34 4 B 26 43 5 The expected observations for this table would be Y. A 27 503 vo || 37. 154 4 343 B 29 497 o 39.846 o 4.657 The resulting Pearson residuals are: Y A 445 of 268 027 B 415 250 .025
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