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A 1,1,2-trichloroethane-acetone solution containing 42% acetone by weight at a flow rate of 1200 kg/h will be extracted at 25°C with water at a flow rate of 2100 kg/h in a reverse flow multi-stage extraction system. The water is impure and contains 2% 1,1,2-trichloroethane by weight. According to the requirement that acetone www/mam should not exceed 5% by weight in the refining phase; a. b. DATA; The quantities and compositions of the extract and the refining phase, Find the winning percentage of acetone, Extract Phase Acetone 0.0596 0.1704 0.2692 0.3088 0.3573 0.4090 0.4605 0.5178 1,1,2- trichloroethane 0.0052 0.0073 0.0102 0.0117 0.0160 0.0210 0.0375 0.0652 H20 Acetone 0.9352 0.0875 0.8223 0.2514 0.7206 0.3852 0.6795 0.4297 0.6267 0.4821 0.5700 0.5395 0.5020 0.5740 0.4170 0.6034 Refining Phase 1,1,2- trichloroethane 0.9093 0.7376 0.5921 0.5392 0.4753 0.4000 0.3370 0.2626 H2O 0.0032 0.0110 0.0227 0.0311 0.0426 0.0605 0.0890 0.1340

A 1,1,2-trichloroethane-acetone solution containing 42% acetone by weight at a flow rate of 1200 kg/h will be extracted at 25°C with water at a flow rate of 2100 kg/h in a reverse flow multi-stage extraction system. The water is impure and contains 2% 1,1,2-trichloroethane by weight. According to the requirement that acetone www/mam should not exceed 5% by weight in the refining phase; a. b. DATA; The quantities and compositions of the extract and the refining phase, Find the winning percentage of acetone, Extract Phase Acetone 0.0596 0.1704 0.2692 0.3088 0.3573 0.4090 0.4605 0.5178 1,1,2- trichloroethane 0.0052 0.0073 0.0102 0.0117 0.0160 0.0210 0.0375 0.0652 H20 Acetone 0.9352 0.0875 0.8223 0.2514 0.7206 0.3852 0.6795 0.4297 0.6267 0.4821 0.5700 0.5395 0.5020 0.5740 0.4170 0.6034 Refining Phase 1,1,2- trichloroethane 0.9093 0.7376 0.5921 0.5392 0.4753 0.4000 0.3370 0.2626 H2O 0.0032 0.0110 0.0227 0.0311 0.0426 0.0605 0.0890 0.1340

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A 1,1,2-trichloroethane-acetone solution containing 42% acetone by weight at a flow rate of 1200 kg/h will be extracted at 25°C with water at a flow rate of 2100 kg/h in a reverse flow multi-stage extraction system. The water is impure and contains 2% 1,1,2-trichloroethane by weight. According to the requirement that acetone should not exceed 5% by weight in the refining phase; a. b. DATA; The quantities and compositions of the extract and the refining phase, Find the winning percentage of acetone, Extract Phase Acetone 0.0596 0.1704 0.2692 0.3088 0.3573 0.4090 0.4605 0.5178 1,1,2- trichloroethane 0.0052 0.0073 0.0102 0.0117 0.0160 0.0210 0.0375 0.0652 H20 Acetone 0.9352 0.0875 0.8223 0.2514 0.7206 0.3852 0.6795 0.4297 0.6267 0.4821 0.5700 0.5395 0.5020 0.5740 0.4170 0.6034 Refining Phase 1,1,2- trichloroethane 0.9093 0.7376 0.5921 0.5392 0.4753 0.4000 0.3370 0.2626 H2O 0.0032 0.0110 0.0227 0.0311 0.0426 0.0605 0.0890 0.1340
Transcribed Image Text:A 1,1,2-trichloroethane-acetone solution containing 42% acetone by weight at a flow rate of 1200 kg/h will be extracted at 25°C with water at a flow rate of 2100 kg/h in a reverse flow multi-stage extraction system. The water is impure and contains 2% 1,1,2-trichloroethane by weight. According to the requirement that acetone should not exceed 5% by weight in the refining phase; a. b. DATA; The quantities and compositions of the extract and the refining phase, Find the winning percentage of acetone, Extract Phase Acetone 0.0596 0.1704 0.2692 0.3088 0.3573 0.4090 0.4605 0.5178 1,1,2- trichloroethane 0.0052 0.0073 0.0102 0.0117 0.0160 0.0210 0.0375 0.0652 H20 Acetone 0.9352 0.0875 0.8223 0.2514 0.7206 0.3852 0.6795 0.4297 0.6267 0.4821 0.5700 0.5395 0.5020 0.5740 0.4170 0.6034 Refining Phase 1,1,2- trichloroethane 0.9093 0.7376 0.5921 0.5392 0.4753 0.4000 0.3370 0.2626 H2O 0.0032 0.0110 0.0227 0.0311 0.0426 0.0605 0.0890 0.1340
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In this question, I did not understand the value of YAN+1. How was it calculated? Is it 0 or 0.02?   

 

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YAN+1=0.02 why did you find it like that YAN+1=0 shouldn't it be??
besides, how can I find out the winning percentage of Acetone %

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