WHICH OF THE FOLLOWING SITUATIONS IS BETTER AND WHY? DIFFERENTIATE THE TWO SITUATIONS AND EXPLAIN YOUR CHOICE IN 2 PARAGRAPHS. A. TEST SCORE OF 90% AND A PERCENTILE RANK OF 20. ( A percentile rank of 20 means the test score lies at 20th position and 90% of data lies below this value and 10% lies above this score. ) B. TEST SCORE OF 70% AND A PERCENTILE RANK OF 90. ( A percentile rank of 90 means the test score lies at 90th position and 70% of data lies below this value and 30% lies above this score.)
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
WHICH OF THE FOLLOWING SITUATIONS IS BETTER AND WHY? DIFFERENTIATE THE TWO SITUATIONS AND EXPLAIN YOUR CHOICE IN 2 PARAGRAPHS.
A. TEST SCORE OF 90% AND A PERCENTILE RANK OF 20. ( A percentile rank of 20 means the test score lies at 20th position and 90% of data lies below this value and 10% lies above this score. )
B. TEST SCORE OF 70% AND A PERCENTILE RANK OF 90. ( A percentile rank of 90 means the test score lies at 90th position and 70% of data lies below this value and 30% lies above this score.)
Trending now
This is a popular solution!
Step by step
Solved in 2 steps