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Which of the following functions is equivalent to f (x) = log₁ (16x)? Hint: There are 4 correct answers! 0 f(x) = log (16) = log (4x) f (x) = log₁ (2x) f(x) = log₁ (16+ x) f (x) = 2x f (x) = f(x) = log(16x) log(4) In(16x) In (4) log(4) f (x) = log(16x) f (x) = g(4) log (16x) f(x) = 2 + log₁

Which of the following functions is equivalent to f (x) = log₁ (16x)? Hint: There are 4 correct answers! 0 f(x) = log (16) = log (4x) f (x) = log₁ (2x) f(x) = log₁ (16+ x) f (x) = 2x f (x) = f(x) = log(16x) log(4) In(16x) In (4) log(4) f (x) = log(16x) f (x) = g(4) log (16x) f(x) = 2 + log₁

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Which of the following functions is equivalent to ƒ (x) = log4 (16x)? Hint: There are 4 correct answers! {_______ƒ (x) = log (¹6r) = log (4x) f(x) = log₁ (2x) f(x) = log (16x) f(x) = 2x f(x) = |__f(x) = log(162) log(4) In(162) In (4) log(4) log(16x) |_ƒ (x) = f (x) log(4) f(x) = 2 + log a log (16x)
Transcribed Image Text:Which of the following functions is equivalent to ƒ (x) = log4 (16x)? Hint: There are 4 correct answers! {_______ƒ (x) = log (¹6r) = log (4x) f(x) = log₁ (2x) f(x) = log (16x) f(x) = 2x f(x) = |__f(x) = log(162) log(4) In(162) In (4) log(4) log(16x) |_ƒ (x) = f (x) log(4) f(x) = 2 + log a log (16x)
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