Which is true with distribution coefficient? I. A partitioning of a compound exist between a mixture of two immiscible phases at equilibrium II. It explains the process when species move from one phase to another phase in immicibel system II. It is used to predict the amount of solute that can be extracted from a solution during extraction O Only I and Il are correct O Only IIl is correct O All are correct O none of the atatement is correct

Which is true with distribution coefficient? I. A partitioning of a compound exist between a mixture of two immiscible phases at equilibrium II. It explains the process when species move from one phase to another phase in immicibel system II. It is used to predict the amount of solute that can be extracted from a solution during extraction O Only I and Il are correct O Only IIl is correct O All are correct O none of the atatement is correct

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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.Consider the following solubility data for various chromates at 25°C Ksp x 10-12 9.0 Ag,CrO4 x 10-10 2.0 Bacro4 x 10-14 1.8 PbCrO4 :The chromate that is the most soluble in water at 25°C on a molar basis is none of these .a Ag2CrO4 .b O .c O BaCro4 .d O PbCrO4
For the aqueous Ni(NH,), complex K, = 5.50 × 10° at 25 °C. Suppose equal volumes of 0.0012 M Ni(NO,). solution and 0.76M NH, solution are mixed. Calculate the equilibrium molarity of aqueous Ni ion. Round your answer to 2 significant digits.
(ISCN Data Report Sheet: Spectrophotometric Determination of an Equilibrium Constant. Part A: Determination of a Calibration Curve; Stnd.1 Std. 2 Stnd. 3 Stnd 4 Sind. 5 Stad. 6 (Но) 0.000090 0.000106 0.000127 0.000189 0.000204 (Fe(SCN)"] Column A 0.432 0.480 0.633 0.831 0.887 Absorbance Column E 0. y= 4339.8x + 0.0258 Equafion of Calibration Line: 0.9904 Correlation Coefficient; 4339.8 Slope (br): Part B: Determination of K Expt. 1 Еxpt, 2 Expt. 3 Expt. 4 Expt. 5 0,00165 0.00165 0.00165 0.00165 000165 (Table 1) 0.00033 0.00066 0.00099 0.001 0.00165 ISCN at (Table 1) 0.290 0.524 0.803 1.024 1.199 [Fe(SCN)*l Column F |Fe"leqt 148.6799 135.1678 142.2659 141 8466 134.2843 Average K:140 448 I
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Pre-Laboratory Assignment: Determination of K, for a Complex lon Formation Name Section A student mixes 5.0 ml of 0.00200 M Fe(NO,), with 5.0 mL 0.00200 KSCN. She finds that the concentration of FESCN in the equilibrium mixture is 0.000125 M. Follow these steps to determine the corresponding experimental value of K, for the reaction of Fe" and SCN to produce this complex ion. Show your calculations for each step below and then place the appropriate value(s) in the equilibrium (or 'ICE') table near the bottom of the page. Step 1. Calculate the molarity of Fe", SCN, and FeSCN" initially present after mixing the two solutions, but prior to any reaction taking place. (M,V, = M,V3) Step 2. Determine the expression and initial value for Q. Then give the appropriate signs of the concentration changes for each species in terms of the reaction's shift, or x, into the ICE table. Step 3. Fill in the equilibrium value for the molarity of FESCN". From this, you can determine the value of x. Step 4.…
Generate the solubility-product expression fora. CuI.b. PbI2.c. BiI3d. MgNH4PO4
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For the aqueous Ni(CN),] complex K,=2.00 × 10³1 at 25 °C. Suppose equal volumes of 0.0090M Ni(NO,) solution and 0.68 M NaCN solution are mixed. Calculate the equilibrium molarity of aqueous Ni ion. Round your answer to 2 significant digits. do M
(ISCN Data Report Sheet: Spectrophotometric Determination of an Equilibrium Constant. Part A: Determination of a Calibration Curve; Stnd.1 Std. 2 Stnd. 3 Stnd 4 Sind. 5 Stad. 6 (Но) 0.000090 0.000106 0.000127 0.000189 0.000204 (Fe(SCN)"] Column A 0.432 0.480 0.633 0.831 0.887 Absorbance Column E 0. y= 4339.8x + 0.0258 Equafion of Calibration Line: 0.9904 Correlation Coefficient; 4339.8 Slope (br): Part B: Determination of K Expt. 1 Еxpt, 2 Expt. 3 Expt. 4 Expt. 5 0,00165 0.00165 0.00165 0.00165 000165 (Table 1) 0.00033 0.00066 0.00099 0.001 0.00165 ISCN at (Table 1) 0.290 0.524 0.803 1.024 1.199 [Fe(SCN)*l Column F |Fe"leqt 148.6799 135.1678 142.2659 141 8466 134.2843 Average K:140 448 I