What distribution has the largest spread? The smallest?
Q: The average final exam score for the statistics course is 81%. A professor wants to see if the…
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Q: The average final exam score for the statistics course is 82%. A professor wants to see if the…
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Q: The average final exam score for the statistics course is 77%. A professor wants to see if the…
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Q: The average fruit fly will lay 400 eggs into rotting fruit. A biologist wants to see if the average…
A: From the provided information, Sample size (n) = 12 Level of significance (α) = 0.05
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Q: The average final exam score for the statistics course is 81%. A professor wants to see if the…
A: Introduction:The null and alternative hypotheses are as follows:H0: μ = 81, vs. H1: μ ≠ 81.When the…
Q: The average final exam score for the statistics course is 75%. A professor wants to see if the…
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Q: The average final exam score for the statistics course is 76%. A professor wants to see if the…
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Q: he average fruit fly will lay 401 eggs into rotting fruit. A biologist wants to see if the average…
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Q: The average final exam score for the statistics course is 74%. A professor wants to see if the…
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Q: The average final exam score for the statistics course is 82%. A professor wants to see if the…
A: a. Suppose μ is the population mean final exam score for students who are given colored pens at the…
Q: The average final exam score for the statistics course is 76%. A professor wants to see if the…
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Q: Determine whether or not the given procedure results in a binomial distribution. If not, identify…
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Q: The average fruit fly will lay 407 eggs into rotting fruit. A biologist wants to see if the average…
A: Answer Given 417,435,426,414,435,414,405,439,414,424,419,429,405,433,391,406 sample size [n] = 16…
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Q: The average final exam score for the statistics course is 75%. A professor wants to see if the…
A: 1. For this study, we should use t-test for a population mean.
Q: The average final exam score for the statistics course is 81%. A professor wants to see if the…
A: 1) The t-test :Here, the sample size is small and sample standard deviation is unknown. Therefore,…
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- The average final exam score for the statistics course is 82%. A professor wants to see if the average final exam score for students who are given colored pens on the first day of class is higher. The final exam scores for the 16 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal. 92, 91, 94, 83, 73, 100, 72, 74, 74, 77, 87, 100, 70, 76, 99, 84 What can be concluded at the the a = 0.05 level of significance level of significance?A die was flipped 15 times, below is the number of upside. Number on left is toss, number on right is upside. 1-2 2-1 3-2 4-4 5-5 6-3 7-1 8-6 9-4 10-2 11-3 12-5 13-1 14-2 15-4 A) Make a table to describe the distribution of number upside. Express it in terms of counts and percent. B) What is the proportion that the number showed upside is bigger than 4? C) What is the proportion that the number showed upside is 3 or smaller?You are given the following set of observations: 98, 77, 26, 33, 88, 90, 79, 81. What would be the mean for this distribution?
- The average final exam score for the statistics course is 74%. A professor wants to see if the average final exam score for students who are given colored pens on the first day of class is higher. The final exam scores for the 14 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal. 82, 85, 97, 74, 84, 87, 65, 63, 79, 97, 69, 61, 83, 78 What can be concluded at the the αα = 0.05 level of significance level of significance? The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > ≠ < = H1:H1: ? p μ Select an answer ≠ = > < The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.)Coach Perkin’s administered a 10 question quiz on golf etiquette to his advanced PE class. The scores for the class were: 10, 9, 9, 10, 6, 7, 9, 5, 6, 3, 9, 7, 6, 9, 6 What is the mode for the distribution? Group of answer choices 6 9 Both 6 and 9 Both 3 and 10The average final exam score for the statistics course is 77%. A professor wants to see if the average final exam score for students who are given colored pens on the first day of class is different. The final exam scores for the 13 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal. 77, 91, 64, 96, 96, 75, 74, 78, 84, 98, 78, 80, 74 What can be concluded at the the a = 0.10 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ?✓ Select an answer ✓ H₁: ? Select an answer c. The test statistic ? ✓ = d. The p-value = e. The p-value is ? ✓ a f. Based on this, we should [Select an answer the null hypothesis. (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.)
- The average final exam score for the statistics course is 81%. A professor wants to see if the average final exam score for students who are given colored pens on the first day of class is higher. The final exam scores for the 16 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal. 81, 81, 96, 78, 92, 94, 87, 92, 75, 87, 69, 98, 68, 95, 98, 92 What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: Select an answer v H1: ? v Select an answer v C. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v f. Based on this, we should Select an answer ♥ the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton mean is significantly higher than…The average fruit fly will lay 421 eggs into rotting fruit. A biologist wants to see if the average will be lower for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 429, 426, 402, 401, 393, 424, 426, 415, 416, 422, 414, 428 What can be concluded at the the αα = 0.05 level of significance level of significance? For this study, we should use Correct The alternative hypothesis would be: H1:H1: Correct Correct Correct The test statistic Correct = (please show your answer to 3 decimal places.) Based on this, we should Correct the null hypothesis. Thus, the final conclusion is that ... Correctc. Age of first heart attack - The horizontal axis is age. The vertical axis is frequency (number of people who had their first heart attack at that age). The population is people in the US who have had at least one heart attack. Shape of distribution: uniform skewed left skewed right symmetric Justification:
- The average fruit fly will lay 421 eggs into rotting fruit. A biologist wants to see if the average wil be lower for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 429, 426, 402, 401, 393, 424, 426, 415, 416, 422, 414, 428 What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use t-test for a population mean b. The alternative hypothesis would be: H: 421 c. The test statistic - -1.358 (please show your answer to 3 decimal places.) d. Based on this, we should fail to reject e. Thus, the final conclusion is that... The data suggest that the population mean number of eggs that fruit fies with this gene modified wil the null hypothesis.Three histograms and three boxplots are given below. Match each histogram (X, Y, and Z) with the corresponding boxplot (A, B, or C). Explain your reasoning. Click the icon to view.the histograms and boxplots. Boxplot P corresponds to Histogram Z because both show a right-skewed distribution that has at least one outlier. Boxplot M corresponds to Histogram Y because both show a left-skewed distribution that has no outliers. Boxplot C corresponds to Histogram X because both show a right-skewed distribution that has at least one outlier.find the p value and explain how it is done.