Using the Kf and Kb équati -7.03 °C-kg-mol. Calculate хтно A certain liquid X has a normal freezing point of 7.50 °C and a freezing point depression constant K- the freezing point of a solution made of 13.8g of glycine (C₂H₂NO₂) dissolved in 450. g of Xy Round you answer to 3 significant digits. TSIO 2 8: 0.45 + 2.86

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Using the Kf and Kb equations with electrolytes
A certain liquid X has a normal freezing point of 7.50 °C and a freezing point depression constant K-7.03 °C-kg-mol. Calculate
the freezing point of a solution made of 13.8g of glycine (C₂H₂NO₂) dissolved in 450. g of X
Round you answer to 3 significant digits.
10.3)
Calculating and using the van't Hoff factor for electrolytes
When 132. g of urea (CH₂N₂O)
than the freezing point of pure X.
are dissolved in 800. g of a certain mystery liquid X, the freezing point of the solution is 7.80 °C less
و
Calculate the mass of sodium chloride that must be dissolved in the same mass of X to produce the same depression in freezing point.
The van't Hoff factor i= 1.68 for sodium chloride in X.
pravid
Solutio
Be sure your answer has a unit symbol, if necessary, and is rounded to the correct number of significant digits.
Mass
132.
800
10.45 =
+2.86
7.800
freezions
X-58.44
The mass
The
mass
freezing
Transcribed Image Text:RFUM Using the Kf and Kb equations with electrolytes A certain liquid X has a normal freezing point of 7.50 °C and a freezing point depression constant K-7.03 °C-kg-mol. Calculate the freezing point of a solution made of 13.8g of glycine (C₂H₂NO₂) dissolved in 450. g of X Round you answer to 3 significant digits. 10.3) Calculating and using the van't Hoff factor for electrolytes When 132. g of urea (CH₂N₂O) than the freezing point of pure X. are dissolved in 800. g of a certain mystery liquid X, the freezing point of the solution is 7.80 °C less و Calculate the mass of sodium chloride that must be dissolved in the same mass of X to produce the same depression in freezing point. The van't Hoff factor i= 1.68 for sodium chloride in X. pravid Solutio Be sure your answer has a unit symbol, if necessary, and is rounded to the correct number of significant digits. Mass 132. 800 10.45 = +2.86 7.800 freezions X-58.44 The mass The mass freezing
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