(12Question 9 hHalf-ReactionStandard Reduction Potential, E (V)Ag* (aq) + e- → Ag(s)+0.80Cu2+ (aq) + 2 e- → Cu(s)+0.34Pb2+ (ag) + 2 e- → Pb(s)-0.13Alš+ (aq) + 3 e → Al(s)-1.66A standard galvanic cell is made using Pb-Pb(NO3), and Cu-Cu(NO,), half-cells. Which of the following modifications to the cell will cause the greatest increase in E cell, and why? Assume all solutionsare 1 M.AReplacing the Cu-Cu(NO,), half-cell with a Ag-AgNO3 half-cell, because the reduction of 1 mol of Ag requires only 1 mol of e, resulting in E cell = +0.67 V.BReplacing the Cu-Cu(NO,), half-cell with a Ag-AgNO3 half-cell, because less current flows through the cell, resulting in E" cell = +0.93 V.Replacing the Pb-Pb(NO,), half-cell with an Al-Al(NO,), half-cell, because the oxidation of Al(s) is more thermodynamically favorable than the oxidation of Pb(s), resulting inE" cell = +2.00 V.DReplacing the Pb-Pb(NO,), half-cell with an Al-Al(NO,), half-cell, because 6 mol of e flow through the cell, resulting in E" cell = +5.66 V.Q Search or enter website name

Since the standard reduction potential of Cu2+ is more than Pb2+, thus Cu2+ will undergo reduction…

uestion 9 D Half-Reaction Standard Reduction Potential, E (V) Ag+ (aq) +e -→ Ag(s) +0.80 Cu2+ (aq) + 2 e Cu(s) +0.34 Pb2+ (aq) + 2 e- Pb(s) -0.13 Al+ (aq) + 3 e- Al(s) -1.66 standard galvanic cell is made using Pb-Pb(NO,), and Cu-Cu(NO,), half-cells. Which of the following modifications to the cell will cause the greatest increase in E cell, and why? Assume all solutio e1 M. Replacing the Cu-Cu(NO,), half-cell with a Ag-AgNO, half-cell, because the reduction of 1 mol of Ag requires only 1 mol of e, resulting in E cell = +0.67 V. Replacing the Cu-Cu(NO,), half-cell with a Ag-AGNO, half-cell, because less current flows through the cell, resulting in E cell = +0.93 V. Replacing the Pb-Pb(NO,), half-cell with an Al-Al(NO,), half-cell, because the oxidation of Al(s) is more thermodynamically favorable than the oxidation of Pb(s), resulting in E' cell = +2.00 V. Replacing the Pb-Pb(NO,), half-cell with an Al-Al(NO,), half-cell, because 6 mol of e flow through the cell, resulting in E" cell = +5.66 V D

uestion 9 D Half-Reaction Standard Reduction Potential, E (V) Ag+ (aq) +e -→ Ag(s) +0.80 Cu2+ (aq) + 2 e Cu(s) +0.34 Pb2+ (aq) + 2 e- Pb(s) -0.13 Al+ (aq) + 3 e- Al(s) -1.66 standard galvanic cell is made using Pb-Pb(NO,), and Cu-Cu(NO,), half-cells. Which of the following modifications to the cell will cause the greatest increase in E cell, and why? Assume all solutio e1 M. Replacing the Cu-Cu(NO,), half-cell with a Ag-AgNO, half-cell, because the reduction of 1 mol of Ag requires only 1 mol of e, resulting in E cell = +0.67 V. Replacing the Cu-Cu(NO,), half-cell with a Ag-AGNO, half-cell, because less current flows through the cell, resulting in E cell = +0.93 V. Replacing the Pb-Pb(NO,), half-cell with an Al-Al(NO,), half-cell, because the oxidation of Al(s) is more thermodynamically favorable than the oxidation of Pb(s), resulting in E' cell = +2.00 V. Replacing the Pb-Pb(NO,), half-cell with an Al-Al(NO,), half-cell, because 6 mol of e flow through the cell, resulting in E" cell = +5.66 V D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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