The titration solution in the cell below had a total volume of 50.0 mL and contained 0.100 M Mg2+ and 1.00 x 10-5 M Zn(EDTA)2- at a pH of 10.00 S.C.E. || Zn(s) | titration solution Zn2* + 2e- Zn(s) E = -0.762 v MgY2: Kf = 6.2 x 108; Zny2-: Kf = 3.2 x 1016. What will be the cell voltage when 10.0 mL of 0.100 M EDTA has been added? (Hint: See Exercise 15-B.) i) Total mmoles of Mg*2 ii) mmoles of EDTA added is iii) mmoles of Mg*2 reacting with EDTA

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The titration solution in the cell below had a
total volume of 50.0 mL and contained
0.100 M Mg2+ and 1.00 x 10-5 M
Zn(EDTA)2- at a pH of 10.00
S.C.E. || Zn(s) | titration solution
Zn2+ + 2e- Zn(s) E = -0.762 V
MgY2-: Kf = 6.2 x 108, ZnY2- : Kf =
3.2 x 1016.
What will be the cell voltage when 10.0 mL
of 0.100 M EDTA has been added? (Hint:
See Exercise 15-B.)
i)
Total mmoles of Mg+2
ii)
mmoles of EDTA added is
iii)
mmoles of Mg*2 reacting with
EDTA
iv)
mmoles of MgY2-
v)
Concentration of MgY2- in M
vi)
mmoles of excess unreacted
Mg*2
vii)
Concentration of Mg*2 in M
viii)
Concentration of EDTA (Y4) in M
ix)
Zn*2{1:NUMERICAL:%100%0.500:0.15}
Total mmoles of
х)
mole of ZnY2- in M
xi)
Concentration of ZnY2- in M
Transcribed Image Text:The titration solution in the cell below had a total volume of 50.0 mL and contained 0.100 M Mg2+ and 1.00 x 10-5 M Zn(EDTA)2- at a pH of 10.00 S.C.E. || Zn(s) | titration solution Zn2+ + 2e- Zn(s) E = -0.762 V MgY2-: Kf = 6.2 x 108, ZnY2- : Kf = 3.2 x 1016. What will be the cell voltage when 10.0 mL of 0.100 M EDTA has been added? (Hint: See Exercise 15-B.) i) Total mmoles of Mg+2 ii) mmoles of EDTA added is iii) mmoles of Mg*2 reacting with EDTA iv) mmoles of MgY2- v) Concentration of MgY2- in M vi) mmoles of excess unreacted Mg*2 vii) Concentration of Mg*2 in M viii) Concentration of EDTA (Y4) in M ix) Zn*2{1:NUMERICAL:%100%0.500:0.15} Total mmoles of х) mole of ZnY2- in M xi) Concentration of ZnY2- in M
xii)
Concentration of Zn2+ in M
xiii)
Potential of the cell in voltage,
Ecell={1:NUMERICAL-1.364:0.1}
Transcribed Image Text:xii) Concentration of Zn2+ in M xiii) Potential of the cell in voltage, Ecell={1:NUMERICAL-1.364:0.1}
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