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The temperatures of the 12 °C water at inlet 13 °C 15 °C 30 °C The temperatures of the 20 °C water at outlet 25 °C

The temperatures of the 12 °C water at inlet 13 °C 15 °C 30 °C The temperatures of the 20 °C water at outlet 25 °C

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The temperatures of the 12 °C water at inlet The temperatures of the 20 °C water at outlet 13 °C 15 °C 25 °C 30 °C Task 1 Explain the system parameters using the Non- Flow Energy Equation Task 2 Derive the Steady Flow Energy Equation from the first principles Task 3 Fill the table below with the missing information for the three cases (i.e., A, B and C) and discuss which system is more efficient. Explain Determine Case A Case B Case C The heat removed by the cooling water. The power input to the compressor The efficiency of the compressor The heat removed by cooling in the air receiver Task 4 Investigate the effect of varying mass flow rate ( m in kg/s) of the cooling water on heat input to the compressor and heat removed by the cooling water. In order to solve this task, you have to assume different mass flow rates to investigate the relationship between mass flow rate, heat input to the compressor, and heat removed by the cooling water, you can use Matlab or EES and present your results in a graph form. Task 5 Produce specific Steady Flow Energy Equation based on the given and stated assumptions in the above problem.
Transcribed Image Text:The temperatures of the 12 °C water at inlet The temperatures of the 20 °C water at outlet 13 °C 15 °C 25 °C 30 °C Task 1 Explain the system parameters using the Non- Flow Energy Equation Task 2 Derive the Steady Flow Energy Equation from the first principles Task 3 Fill the table below with the missing information for the three cases (i.e., A, B and C) and discuss which system is more efficient. Explain Determine Case A Case B Case C The heat removed by the cooling water. The power input to the compressor The efficiency of the compressor The heat removed by cooling in the air receiver Task 4 Investigate the effect of varying mass flow rate ( m in kg/s) of the cooling water on heat input to the compressor and heat removed by the cooling water. In order to solve this task, you have to assume different mass flow rates to investigate the relationship between mass flow rate, heat input to the compressor, and heat removed by the cooling water, you can use Matlab or EES and present your results in a graph form. Task 5 Produce specific Steady Flow Energy Equation based on the given and stated assumptions in the above problem.
Project 2 You are an engineer working in a factory that produce heavy machines, one of the compressors had a problem with heat waste so you are required to calculate the heat removed from the system. Air is drawn in at the intake and compressed in a water cooled reciprocating air compressor. The air passes to an air receiver. Cooling Water OUT Air latake Filter Receiver Low Pressure Air IN Cooling Water Compressor High Pressue Air OUT Elechicity IN Figurel: Layout of industrial gas compressor with an air receiver The given information is summarized in the table below for three different cases |Given Parameters Power delivered by the 20 kW electric motor into the Case A Case B 25 kW Case C 30 kW compressor Mass flow rate of the air 0.3 kg drawn The receiver pressure Atmospheric temperature The temperature of the 30 °C | air entering the receiver The temperature of the 15 °C air leaving the receiver Cooling water flows |0.5 kg I kg 12 bar gauge 20 °C 13 bar gauge 23 °C 15 bar gauge 25 °C 35 °C 40 °C 20 °C 25 °C 0.5 kg 0.7 kg I kg
Transcribed Image Text:Project 2 You are an engineer working in a factory that produce heavy machines, one of the compressors had a problem with heat waste so you are required to calculate the heat removed from the system. Air is drawn in at the intake and compressed in a water cooled reciprocating air compressor. The air passes to an air receiver. Cooling Water OUT Air latake Filter Receiver Low Pressure Air IN Cooling Water Compressor High Pressue Air OUT Elechicity IN Figurel: Layout of industrial gas compressor with an air receiver The given information is summarized in the table below for three different cases |Given Parameters Power delivered by the 20 kW electric motor into the Case A Case B 25 kW Case C 30 kW compressor Mass flow rate of the air 0.3 kg drawn The receiver pressure Atmospheric temperature The temperature of the 30 °C | air entering the receiver The temperature of the 15 °C air leaving the receiver Cooling water flows |0.5 kg I kg 12 bar gauge 20 °C 13 bar gauge 23 °C 15 bar gauge 25 °C 35 °C 40 °C 20 °C 25 °C 0.5 kg 0.7 kg I kg
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