The motion of a simple pendulum is very close to Símple Harmoníc Motion (SHM) only when holds true when is the angle is small (small angle approxímation). In such a case, prove that Farc in Questíon 3 is: F Mg. arc=- L

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I have answered a question before which is the
component of the weight of M that is directed along the arc (Farc) of the motion of M which I got mg sin Ө.

But how do I prove that the F arc that I got which is mg sin Ө is

Farc =−??/L (x)

Mg
Transcribed Image Text:Mg
The motion of a simple penduflum is very close to Símple Harmonic Motion (SHM)
only when holds true when is the angle is small (small angle approxímation). In such a
case, prove that Farc in Question 3 is:
F
arc=- Mg,r
L
Transcribed Image Text:The motion of a simple penduflum is very close to Símple Harmonic Motion (SHM) only when holds true when is the angle is small (small angle approxímation). In such a case, prove that Farc in Question 3 is: F arc=- Mg,r L
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