The household size in a certain neighborhood varies from 1 to 6 The probability distribution of the size of arandom household, is as follows:I P(z)0.030.10.190.37240.150.120.04Use the above probability distribution table to find the following:a. P(3 < X < 5)(Round the answer to 2 decimals)b. P(1 < X < 3) =(Round the answer to 2 decimals)c. P(X < 6) =(Round the answer to 2 decimals)%3D

Answered: Image /qna-images/answer/0c39592a-cbc6-449b-8704-92ac229a83a6.jpg

Answered: The household size in a certain…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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A sociologist surveyed the households in a neighboring town and recorded the number of dependent children in the household. The following probability distribution was created based on the survey. Use the probability distribution to answer the following questions x 0 1 2 3 4 P(x) 0.07 0.20 0.38 0.22 0.13 What is the probability that a surveyed household stated they had more than 2 dependent children in the household? (round your answer to 2 decimal places)
The probability distribution for the number of Customer per day at the Sunset Spa is shown below: Number of Customers(X) 40 41 42 43 44 Probability P(X) 0.1 0.20 3b 0.21 0.12 Determine the: value of b probability that at least 42 customers will be in the diner per day
Let X = {Email, In Person, Instant Message, Text Message}; P(Email) = 0.06 P(In Person) = 0.55 P(Instant Message) = 0.24 P(Text Message) = 0.15 Is this model a probability distribution? A. Yes. B. No. C. Maybe.
Determine the required value of the missing probability to make the distribution a discrete probability distribution. P(4) = (Type an integer or a decimal.) ×3 X 4 5 6 P(x) 0.27 ? 0.32 0.14
Find the mean, variance and standard deviation for the probability distribution given below: X -5 2 12 10 P(X) 0.553 0.136 0.213 0.098
The following table lists certain values of x and their probabilities. Verify whether or not it represents a valid probability distribution. P(x) 0 0.31 1 0.30 2 0.19 3 0.16 The table a valid probability distribution.
Determine the required value of the missing probability to make the distribution a discrete probability distribution. P(4) = (Type an integer or a decimal.) O Bi TEH a 31 TH X 3 4 5 6 P(x) 0.29 ? 0.37 0.11
Determine whether the following is a probability distribution. If not, identify the requirement that is not satisfied. ** view image options: Probability Distribution Not a Probability Distribution
what probability value would be needed to complete the following probability distribution? X -2 -1 0 1 2 P(X) 0.13 0.14 0.16 0.29
Determine the required value of the missing probability to make the distribution a discrete probability distribution. P(4) = (Type an integer or a decimal.) X P(x) 3 0.16 4 ? 5 0.40 6 0.15 ...
Determine the required value of the missing probability to make the distribution a discrete probability distribution. X P(x) 3 0.22 4 ? 5 0.34 6. 0.25 ..... P(4) = (Type an integer or a decimal.) %D
A basketball player makes 70% of her free throws. When fouled, she gets to take two free throws. Let X represent the number of free throws made in two tries. The probability distribution for the number of free throws she makes in two attempts is summarized in the following table: Number of free throws made Probability P(X 1) P(X ≤1) 0 O P(X ≥ 1) 0.09 1 The probability statement representing that she makes at least one free throw is expressed as 0.42 2 0.49

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