The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If 1 mole of ice is melted under these conditions, what will be a) The work done in cal? b) The change in internal energy in cal? c) The change in entropy in cal? Note that 1 literxatmosphere is equal to 101.325 joule

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Chapter1: Chemical Foundations
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Sekton)
The heat of melting of ice at 1
atmosphere pressure and 0°C is
1.4363 kcal/mol. The volume of ice is
0.0196 liter and the volume of water
is 0.018 liter. If 1 mole of ice is melted
under these conditions, what will be
a) The work done in cal? b) The
change in internal energy in cal? c)
The change in entropy in cal? Note
that 1 literxatmosphere is equal to
101.325 joule
Given:
C 1-4363 Kcal/male
тся
= 0.0196 liter
Val of ice
Vel of water = 0·018 liter
(a) Work done
W
Pdv
-
= 1 (0-018-0-0196)
W = 0.0016 cal
(b) Change in internal energy
AE = Q - W
= 1-4363 X 10³-0-0016
AE = 1436-29 cal
(C) Change in Entrepy (AS) = 2
AS = 1436-30
273
AS = 5-261
Liter xatm=101.325 Joule
J=
J⇒cal
what??
Transcribed Image Text:Sekton) The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If 1 mole of ice is melted under these conditions, what will be a) The work done in cal? b) The change in internal energy in cal? c) The change in entropy in cal? Note that 1 literxatmosphere is equal to 101.325 joule Given: C 1-4363 Kcal/male тся = 0.0196 liter Val of ice Vel of water = 0·018 liter (a) Work done W Pdv - = 1 (0-018-0-0196) W = 0.0016 cal (b) Change in internal energy AE = Q - W = 1-4363 X 10³-0-0016 AE = 1436-29 cal (C) Change in Entrepy (AS) = 2 AS = 1436-30 273 AS = 5-261 Liter xatm=101.325 Joule J= J⇒cal what??
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