Answered: The ha lf-lives for the forward and…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Question

The ha lf-lives for the forward and backward reactions of a reaction that is first-order in both directions are 24 ms and 39 ms respectively. Calculate the correspond ingre laxation time for return to equilibrium after a temperature
jump.

Expert Solution

Step 1

Given:

Half-life for the forward reaction, ${(t_{1 / 2})}_{1} = 24 ms$

Half-life for the backward reaction, ${(t_{1 / 2})}_{2} = 39 ms$

Step 2

For the first-order reaction,

$\Rightarrow Half life, t_{1 / 2} = \frac{0.693}{K}$

where,

K=rate constant

Then,

$\Rightarrow K_{1} = \frac{0.693}{{(t_{1 / 2})}_{1}} = \frac{0.693}{24 ms} = 0.029 {ms}^{- 1}$

$\Rightarrow K_{2} = \frac{0.693}{{(t_{1 / 2})}_{2}} = \frac{0.693}{39 ms} = 0.018 {ms}^{- 1}$

where K₁ and K₂ are the rate constants for the forward and backward reactions respectively.

Step by step

Solved in 3 steps

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions