The grade-point average of 20 BS Psychology seniors selected at random from the graduating class are as follows: 3.2 1.9 2.7 2.4 2.8 2.9 3.8 3.0 2.5 3.3 1.8 2.5 3.7 2.8 2.0 3.2 2.3 2.1 2.5 1.9 If you are asked to construct a frequency distribution for the given data, what would be the possible number of class intervals? CHOICES: 6 to 7 4 4 to 5 5 to

The grade-point average of 20 BS Psychology seniors selected at random from the graduating class are as follows: 3.2 1.9 2.7 2.4 2.8 2.9 3.8 3.0 2.5 3.3 1.8 2.5 3.7 2.8 2.0 3.2 2.3 2.1 2.5 1.9 If you are asked to construct a frequency distribution for the given data, what would be the possible number of class intervals? CHOICES: 6 to 7 4 4 to 5 5 to

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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This problem will take you through calculating the mean for grouped data by hand.The reason that the class midpoint is used in the table below is because it is the expected value for the average score in each class. Part A: Lower Class Limit Upper Class Limit Frequency Class midpoint Frequency times midpoint 60 64 13 65 69 17 70 74 15 75 79 7 77 539 80 84 5 82 410 85 89 5 87 435 90 94 3 92 276 95 99 1 97 97 100 104 1 102 102 Part B: Now add up the last column of the table above.
Refer to the following plot. Distribution of ê Distribution of ê2 Which statement is the most accurate? Select one: a. Point estimator 1 is better than point estimator 2 because point estimator 1 has a lower mean square error b. Point estimator 2 is better than point estimator 1 because point estimator 2 has higher variance It is unclear which estimator is better d. Point estimator 1 is better than point estimator 2 because point estimator 1 is unbiased estimator е. Point estimator 2 is better than point estimator 1 because point estimator 2 is an unbiased estimator
Here is a frequency distribution table (FDT) for a small data set: data value frequency 37 16 38 24 39 11 40 30 41 14 Find the following measures of central tendency. mean (7) = (Please show your answer to one decimal place.) median (Please enter an exact answer.) mode = (Please enter an exact answer.)
The given data represent the number of people from a town, aged 25-64, who subscribe to a print magazine. Construct a frequency polygon. Applying a loose interpretation of the requirements for a normal distribution, does the data appear to be normally distributed? Why or why not?...Question content area top rightPart 1AgePeople 25-3435-4445-5455-64 104716307113 Question content area bottomPart 1Construct a frequency polygon using the data. Choose the correct graph below.A.19.569.501000AgeFrequency A graph has a horizontal axis labeled "Age" from 19.5 to 69.5 in intervals of 5 and a vertical axis labeled "Frequency" from 0 to 1000 in intervals of 100. The following six approximate points are plotted and are connected from left to right by line segments: (20, 0); (30, 100); (40, 720); (50, 300); (60, 120); (70, 0).B.19.569.501000AgeFrequency A graph has a horizontal axis labeled "Age" from 19.5 to 69.5 in intervals of 5 and a vertical axis labeled "Frequency" from 0 to 1000…
TOPIC 3: Identifying Sampling Distribution of Statistics (sample mean). A population consists of the values (1, 4, 3, 2). Consider samples of size 2 that can be drawn from this population. Complete the following table. Sample Sample Mean Frequency Probability P(x)
We will rank the y-values of the following data set: x y -2 -11 -0.8 -11.9 0.7 11.7 1.7 12.2 2.4 1.8 4.6 9.4 6 11.9 7.8 33.4 8.4 27 9.7 21.5 The scatterplot of the data looks like this: 123456789101112-1-2-3-4-5123456789101112131415161718192021222324252627282930313233343536-1-2-3-4-5-6-7-8-9-10-11-12-13-14 Fill in the following table: x y x-rank y-rank -2 -11 1 -0.8 -11.9 2 0.7 11.7 3 1.7 12.2 4 2.4 1.8 5 4.6 9.4 6 6 11.9 7 7.8 33.4 8 8.4 27 9 9.7 21.5 10
Here is a random sample of the body temperature of 25 young adults. 96 96.7 97 97 97 97 97.1 97.1 97.2 97.3 97.3 97.4 97.5 97.6 97.7 97.7 97.7 97.9 97.9 97.9 98 98 98.1 98.3 98.5 Complete the frequency distribution table by entering the cumulative relative frequency. Temperature Group Frequency Relative Frequency CumulativeRelative Frequency 96 ≤ x < 96.31 1 1/25 96.31 ≤ x < 96.62 0 0/25 96.62 ≤ x < 96.93 1 1/25 96.93 ≤ x < 97.24 7 7/25 97.24 ≤ x < 97.55 4 4/25 97.55 ≤ x < 97.86 4 4/25 97.86 ≤ x < 98.17 6 6/25 98.17 ≤ x < 98.48 1 1/25 98.48 ≤ x < 98.79 1 1/25
The monthly expenditures on grocery shopping for all households in a town has a mean of $400 and a standard deviation of 75. The distribution of these monthly expenditures is symmetric and bell-shaped. What percentage of households had a monthly expenditure of between $325 and $400 on groceries in this town? O 99.7% O 689% O 47.5% O 34%
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The following data are ages of infants (in months) at which they walked alone. These sample data were obtained from two populations. Sample A 9.8 11 9.5 9.8 10 13 10 14 10 9 10 9.5 Sample B 12 9.5 9.5 14 12 14 13 12 12 14 14 13 Compare the two groups as to their mean, median and mode. Central Tendency A B Mean ____________ ____________ Median ____________ ____________ Mode (s) ____________ ____________ Midrange ____________ ____________
Mr. Akram handles his own investment and has done for so many years. Listed below is the holding time between purchase and sale of his collection of stock. 11 11 9 15 8 8 12 5 9 8 5 5 14 9 10 11 3 9 8 6 8 9. 5 11 4 8 12 8 6 11 9 7 Create the frequency distribution from above mentioned information? About 75% of stock sells in what time? Draw the cumulative frequency distribution.
The mean # of hours worked