The First Adiabatic Invariant says the number of magnetic field lines enclosed by an orbiting particle remains constant. This implies that if the magnetic field intensity increases along the particle's trajectory, its gyroradius must decrease in order to enclose a constant number of field lines. For the following questions, assume a proton with pitch angle a = 45° at an altitude of 1000 km over the geomagnetic equator with kinetic energy = 1 MeV.

icon
Related questions
Question

According to the information provided. Can you solve the problem?

Notice that the formula to solve that is: Magnetic Moment of the proton = Ke * Sin (alfa) / B

Where Ke = Kinetic Energy

Alfa = the angle 45

B= electromagnetic field

Click to see additional instructions
Using the information provided above, calculate the magnetic moment (µ) of the proton. Report your answer in scientific notation to 2 significant digits. The units of u are
A·m? or equivalently J/T.
Transcribed Image Text:Click to see additional instructions Using the information provided above, calculate the magnetic moment (µ) of the proton. Report your answer in scientific notation to 2 significant digits. The units of u are A·m? or equivalently J/T.
The First Adiabatic Invariant says the number of magnetic field lines enclosed by an orbiting particle remains constant. This implies that if the magnetic field intensity increases along
the particle's trajectory, its gyroradius must decrease in order to enclose a constant number of field lines.
For the following questions, assume a proton with pitch angle a = 45° at an altitude of 1000 km over the geomagnetic equator with kinetic energy = 1 MeV.
Transcribed Image Text:The First Adiabatic Invariant says the number of magnetic field lines enclosed by an orbiting particle remains constant. This implies that if the magnetic field intensity increases along the particle's trajectory, its gyroradius must decrease in order to enclose a constant number of field lines. For the following questions, assume a proton with pitch angle a = 45° at an altitude of 1000 km over the geomagnetic equator with kinetic energy = 1 MeV.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer