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The feed to a propylene ammoxidation process contains 14.55 % of C3H, by mass, 7.0 % ammonia by mass, and 78.45 % air by mass. A fractional conversion of 30.0% of the limiting reactant is achieved, taking 1000 kg feed as a basis, determine the ratio of the unreacted oxygen to the feed by mass, the percentage by which each of the other reactions is in excess, and the mass amounts of all product gas constituents for a 30% conversion of the limiting reactant Feed = 100 mole P=? Reactor * = 0.1455 - 0.07 xr = 0.7845 =? =? C,H, + NH, +3/202 - C,H,N + 3H,0

The feed to a propylene ammoxidation process contains 14.55 % of C3H, by mass, 7.0 % ammonia by mass, and 78.45 % air by mass. A fractional conversion of 30.0% of the limiting reactant is achieved, taking 1000 kg feed as a basis, determine the ratio of the unreacted oxygen to the feed by mass, the percentage by which each of the other reactions is in excess, and the mass amounts of all product gas constituents for a 30% conversion of the limiting reactant Feed = 100 mole P=? Reactor * = 0.1455 - 0.07 xr = 0.7845 =? =? C,H, + NH, +3/202 - C,H,N + 3H,0

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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Q1 The feed to a propylene ammoxidation process contains 14.55 % of C,H, by mass, 7.0 % ammonia by mass, and 78.45 % air by mass. A fractional conversion of 30.0% of the limiting reactant is achieved, taking 1000 kg feed as a basis, determine the ratio of the unreacted oxygen to the feed by mass, the percentage by which each of the other reactions is in excess, and the mass amounts of all product gas constituents for a 30% conversion of the limiting reactant P= ? Feed = 100 mole Reactor x = 0.1455 =? x = 0.07 =? no. * = 0.7845 =? =? C3H, + NH, + 3/202 C3H3N + 3H,0 Q2 Sulphur trioxide gas is obtained by the combustion of pyrites (FeS,) according to the following reaction: 4FES2 + 1502-2Fe,03 + 8S03 The reaction is accompanied by the following side reaction: 4FES2 + 1102 – 5FE203 + 8502 Assume that 80% (weight) of the pyrites charged reacts to give sulphur trioxide and 20% reacts giving sulphur dioxide. a) How many kilograms pf pyrites charged will give 100 kg of SO,? b) How many kilograms of oxygen will be consumed in the reaction? Mwt: CH, = 42, NH3 = 17,02 = 32, C,H,N = 53, H20 = 18, N2 = 28, FeSz = 120 Fe,0, = 136, So, = 80, So, = 64 >
Transcribed Image Text:Q1 The feed to a propylene ammoxidation process contains 14.55 % of C,H, by mass, 7.0 % ammonia by mass, and 78.45 % air by mass. A fractional conversion of 30.0% of the limiting reactant is achieved, taking 1000 kg feed as a basis, determine the ratio of the unreacted oxygen to the feed by mass, the percentage by which each of the other reactions is in excess, and the mass amounts of all product gas constituents for a 30% conversion of the limiting reactant P= ? Feed = 100 mole Reactor x = 0.1455 =? x = 0.07 =? no. * = 0.7845 =? =? C3H, + NH, + 3/202 C3H3N + 3H,0 Q2 Sulphur trioxide gas is obtained by the combustion of pyrites (FeS,) according to the following reaction: 4FES2 + 1502-2Fe,03 + 8S03 The reaction is accompanied by the following side reaction: 4FES2 + 1102 – 5FE203 + 8502 Assume that 80% (weight) of the pyrites charged reacts to give sulphur trioxide and 20% reacts giving sulphur dioxide. a) How many kilograms pf pyrites charged will give 100 kg of SO,? b) How many kilograms of oxygen will be consumed in the reaction? Mwt: CH, = 42, NH3 = 17,02 = 32, C,H,N = 53, H20 = 18, N2 = 28, FeSz = 120 Fe,0, = 136, So, = 80, So, = 64 >
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