The current i in electric circuit containing resistance R, and inductance L in series with a constant voltage source ɛ. potential difference on resistance is iR di potential difference on inductance is L dt when t-0, i-0. i(1) =(1-e")→fS()=? R PA) f(t) = (R*L)t OB) f(t) = - (L/R)t C) f(t) = - (1/(R*L))t OD) f(t) = - (R/L)t PE) f(t) = (R/L)t

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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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The current i in electric circuit containing resistance R,
and inductance L in series with a constant voltage source ɛ.
potential difference on resistance is iR
di
potential difference on inductance is L
dt
37 -
when t=0, i=0.
i(t) =
(1-e/®)→ f(1)=?
R
O A) f(t) = (R*L)t
O B) f(t) = - (L/R)t
OC) ft) = - (1/(R*L))t
OD) f(t) = - (R/L)t
O E) f(t) = (R/L)t
Transcribed Image Text:The current i in electric circuit containing resistance R, and inductance L in series with a constant voltage source ɛ. potential difference on resistance is iR di potential difference on inductance is L dt 37 - when t=0, i=0. i(t) = (1-e/®)→ f(1)=? R O A) f(t) = (R*L)t O B) f(t) = - (L/R)t OC) ft) = - (1/(R*L))t OD) f(t) = - (R/L)t O E) f(t) = (R/L)t
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