The 115-mm-diameter steel shaft is subjected to the torques shown. T1 = 14 kN-m, T2 = 2 kN-m, T3 = 2 kN-m. Determine the angle of twist (degrees) of the end B. Use L1 = 0.75 m., L2 = 0.53 m., L3 = 0.69 m. Shear modulus = 71 GPa.

The 115-mm-diameter steel shaft is subjected to the torques shown. T1 = 14 kN-m, T2 = 2 kN-m, T3 = 2 kN-m. Determine the angle of twist (degrees) of the end B. Use L1 = 0.75 m., L2 = 0.53 m., L3 = 0.69 m. Shear modulus = 71 GPa.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: The bell-crank mechanism is in equilibrium for an applied load of P = 35 kN. Assume that a = 240 mm,…

A: Given Data Determine the average shear stress in the pin-B.

Q: A hollow steel [G = 12,000 ksi] shaft with an outside diameter of 3.50 in. will be subjected to a…

A: Given data G = 12,000 ksi Outside diameter (do) = 3.5 in Torque (T) = 3810 lb-ft Permissible…

Q: View Policies Current Attempt in Progress A compound shaft consists of segment (1), which has a…

Q: The shaft shown is supported by at A and at C. If the material has an allowable bending stress of 24…

A: The bending equation is as follows, σy = MIWhere,σ = Bending stressy = Distance between neutral axis…

Q: The shaft consisting of steel and aluminum segments carries the torques T and 2T. Find the largest…

Q: The bell-crank mechanism is in equilibrium for an applied load of P = 11 kN. Assume that a = 200 mm,…

A: Given Data Determine the bearing stress in the bell crank at pin-B.

Q: depth of the neutral axis.

A: Given: Width of the beam, b = 200 mm Depth of the beam, D = 400 mm Clear cover, cc = 40 mm Diameter…

Q: Solve the angle of twist on a solid shaft, with 5cm radius and 50cm length, if the torque applied is…

Q: er must exert a force of P 3800 lbs at B as shown. The lever lengths are a= 11.5 in. ar or the lever…

A: Section modulus is z=Mσz=31734.518 lb-in10500 psiz=3.0223in3

Q: P B L 3 in. The largest allowable length Lis -18 3 in. 4 in. ft.

Q: Rod BD is made of steel (E = 29 × 106 psi) and is used to brace the axially compressed member ABC.…

Q: 2. The structure, the plan of which is shown below, supports a udl of 1kN/m over lengths AB, BC, DE,…

A: given datafindmoment, torque and shear at each of the fixed end

Q: Mansard roof truss is loaded as shown. Determing the force in members EG in kN. P = 6.5 kN and x =…

A: Consider the F.B.D diagram of mansard roof truss Apply the moment equilibrium equation about point…

Q: A)Determine the force in the 4-ft rod (in pounds). B)Determine the force in the 6-ft rod (in…

Q: A steel shaft is loaded as shown. Knowing that T₁ = 1000 N.m, T₂ = 1600 N.m, L=250 mm, d 40 mm, D =…

A: Given: T1 = 1000N .m T2 =1600 N.m, L = 250mm , d =40 mm, D = 45mm Required : Maximum shear stress…

Q: Two forces, each of magnitude P, are applied to the wrench. The diameter of the steel shaft AB is…

A: Calculate the value of P using both shear stress criteria and angle of twist criteria. The criteria…

Q: normal Ja-25° K → P= AB kN

A: Given data: P=53 KNA=1200 mm2α=25o Calculating normal stress on the plane a-a:…

Q: A hollow steel [G= 12,000 ksi] shaft with an outside diameter of 3.50 in. will be subjected to a…

Q: An axial force P and a bi-axial moment M are applied on the section shown below simultaneously. The…

A: Introduction : Bending equation : (M/I) = (f/y) M = resistance moment I = moment of inertia f =…

Q: Prob 2. The rigid bar below is supported by two copper bars (Ecopper = 90 GPa) and two brass bars…

A: Given data : Ecopper = 90 Gpa , Ebrass= 120 Gpa , diameters of all bars = 20mm , Load = 20000 N Find…

Q: A solid stainless steel [G = 12,500 ksi] shaft that is 30 in. long will be subjected to a pure…

Q: Mechanics

Q: The bell-crank mechanism is in equilibrium for an applied load of P = 39 kN. Assume that a = 290 mm,…

Q: A steel shaft is loaded as shown. Knowing that T₁ = 600 N.m, T₂ = 2600 Nm, L=250 mm, -40 mm, D=45…

A: Given data in question Torque 600 & 2600 Nm Length 250 mm Diameter 40 & 45 mm Modulus of…

Q: A solid stainless steel [G= 12,500 ksi] shaft that is 30 in. long will be subjected to a pure torque…

A: Solution is attached below as

Q: 50 lb-ft T2 (1) 30 lb-ft A (3) B C D Assume for the above sketch that the shaft is restrained from…

Q: The 600mm diameter steel shaft is subjected to the torques shown. Determine torsion at each section.…

Q: A A. The weight of the crate B. The internal force in rod AC 60° -60° C For the figure above, rods…

Q: www. WE A helical spring is fabricated by wrapping wire 3/4 in. in diameter around a forming…

A: Appreciate if there is detailed work with explanation and finds you helpful for ease of…

Q: A hollow steel [G= 12,000 ksi] shaft with an outside diameter of 3.50 in. will be subjected to a…

A: Given data of Hollow steel shaft :- G = 12 * 103 Ksi = 12 * 106 lb /in2 Outside diameter (do) = 3.50…

Q: D, 3 Use the diagram shown above. Given • D= 10 ft • D2= 7 ft • D3=4 ft • W - 500 #/ft Solve for the…

A: Figure is as shown

Q: A 1 2-inch diameter solid round steel bar must transmit a torque of 6000 in-lb and another moment…

A: If the force can cause the deformation of a material by slippage along the plane or parallel to the…

Q: A solid stainless steel [G= 12,500 ksi] shaft that is 30 in. long will be subjected to a pure torque…

Q: The 60mm diameter steel shaft is subjected to the torques shown. Draw the FBD using double arrow…

Q: the minimum diameter of the bolt at B if the shearing stress in the bolt is not to exceed 14000 psi.…

Q: Dron Acompound steel [G=80 GPa) shaft consists of a solid 110-mm-diameter segment (1) and a solid…

A: Given data, G = 80 GPa Solid shaft 1 diameter = 110 mm Solid shaft 2 diameter = 56 mm Allowable…

Q: Thumbs-Up will be given. Write the complette solutions legibly. Answer in 3 decimal places…

A: Solution: Given: DL = 6 kNm LL = 9 kNm Factored Load: P=1.2 DL + 1.6 LL=1.2×6+1.6×9P=21.6 kNm DL = 6…

Q: A hollow steel [G= 12,000 ksi] shaft with an outside diameter of 3.50 in. will be subjected to a…

A: Given, G = 12000 ksi Outside dia = 3.5 inch Maximum stress = 8000 psi T = 3730 lb-ft Angle of twist…

Q: The bell-crank mechanism is in equilibrium for an applied load of P = 15 kN. Assume that a = 240 mm,…

Q: hollow steel [G= 12,000 ksi] shaft with an utside diameter of 3.50 in. will be subjected to pure…

A: Given data of Hollow steel shaft :- G = 12 * 103 Ksi = 12 * 106 lb /in2 Outside diameter (do) =…

Q: A 13-mm-diameter steel (E = 193 GPa) rod (2) is connected to a 27-mm-wide by 10-mm-thick rectangular…

Q: A 1.00-in.-diameter solid steel shaft supports loads PA = 180 lb and Pc = 240 lb shown below. Assume…

A: Diameter of shaft (d) = 1 in. Determine the maximum bending stress and it's location.

Q: The bracket ABCDE is hinged at A and has a roller support resting on the angled surface, with a =…

A: The following figure shows the Free body diagram of the bracket. The reaction at hinge A is VA and…

Q: The circular steel shaft is subjected to two torques as shown. The segment AB is hollow, with…

A: Given Data : G = 12 X 106 psi Outside diameter = 1 inches inside diameter = 1/2 inches Determine :…

Q: Situation 13 Using method of sections, determine the internal force of members 3-6 and 5-7. Use L =…

Q: A hollow steel [G = 12,000 ksi] shaft with an outside diameter of 3.50 in. will be subjected to a…

Concept explainers

British Gravitational Bg System Of Units

Measuring is the comparison of a particular physical quantity with its reference value. A unit is a fixed physical quantity. The length is a physical quantity. A physical quantity is the product of a unit and the numerical value we need to compare with. 

Question

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

The solid 34 mm diameter steel [E = 200 GPa] shaft supports two belt pulleys. For the loading shown, determine: (a) the shaft deflection at pulley B. (b) the shaft deflection at pulley C. Assume P = 810 N, Q = 480 N, LAB = 260 mm, LBC = 400 mm
A simple torsion-bar spring is shown. The shear stress in the steel [G= 11,500 ksi] shaft is not to exceed 8800 psi, and the vertical deflection of joint D is not to exceed 0.400 in. when a load of P = 3000 lb is applied. Neglect the bending of the shaft and assume that the bearing at C allows the shaft to rotate freely. Determine the minimum diameter required for the shaft. Use dimensions of a = 70 in., b = 24 in., and c = 24 in. a b Answer: d= D P B in. C
The 600mm diameter steel shaft is subjected to the torques shown. Determine torsion at each section. Assume G = 75 GPa. P=74 1.5P= 1.5(74) = 111 kNm 3P= 3(74)= 222kNm
3 mm- 4. The cross section of the steel tube (G = 11 x 106) as shown carries a 50 kip-in torque. Calculate (a) the maximum shear stress and (b) the angle of twist per foot of length. Use 2 decimal places in every solved value. mm 2mm mm 3 mm mm- 8 2 of 2
A 16-mm-diameter steel [E = 200 GPa] rod (2) is connected to a 50- mm-wide by 8-mm-thick rectangular aluminum [E = 70 GPa] bar (1), as shown in Figure PP5.3-2. Determine the force P required to stretch the assembly 3.00 mm. (1) 0.45 m Answer in kN rounded-off to 2 decimal places B 1.30 m Figure PP5.3-2 I
1. Answer Set A only
NEED IN 1 HOUR PLEASE THANK U A hollow steel shaft 10 ft long must transmit a torque of 250,000 lb-in. The total angle of twist in this length is not to exceed 2.5 degrees and the allowable shearing stress is 12,000 lb/sq.in. Determine the inside and outside diameters of the shaft if G = 12 x 106 lb/sq.in. The action is elastic.
Q4/ The rigid beam is supported by a pin at A and two steel wires BD and CE. Each rod has a diameter of d. If the load P on the beam causes the end C to be displaced h downward, determine the normal strain developed in wires CE and BD and the applied load P. Assume E steel = 200 Gpa and a= 1.5 m, b= 1lm, d=30 mm, h= 8 mm 2а b a - a
120 mm 30° F= 210 N y 1. L--x 150 mm The 210N force is applied to the end of body OAB. If e= 55-degree, determine the equivalent force-couple system at the shaft axis O, in Nm.
The 6m long steel shaft has a torque of 12 kN-m applied at the free end. The angle of twist of the shaft is limited to 3". Find the diameter of the shaft. Use G = 75 GPa. 12 AN - m Oa. 75 mm Ob. 102 mm O. 130 mm Od.250 mm
Ql:- The system of gears B and C take out power 150 and 175 hp respectively from a motor A that has 325hp, Find the shaft dimeter if the allowable shear stress is 6250 psi and the angle of twist between gear C and motor is 2 degree. Let G=11.5 x 10° psi. Gear Gear Motor A B
The motor A delivers 3000 hp to the shaft at 1500 rev/min, of which 1000 hp is removed by gear B and 2000 hp is removed by gear C. Determine (a) the maximum shear stress in the shaft; and (b) the angle of twist of end D relative to end A. Use G = 12 x 106 psi for steel, and assume that friction at bearing D is negligible. A 4 in. 3.5 in. 3.5 in. ID В C te-4 ft- | 2 ft - 6 ft-