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Table 2 X Z 52 124 79 69 137 83 For Table 2, determine the confidence intervals of: 1. The mathematical expectation. 2. The variance. 3. The variation of the input quantity. Table values: a = 0.05 T(a/2, v= 1) = 12.7062 T(a/2, v= 2) = 4.3027 T(a/2, v= 3) = 3.1825 T(a/2, v= 4) = 2.7765 T(a/2, v= 8) = 2.3060 F(a/2, 2, 2) = 39.0000 F(a/2, 3, 3) = 15.4392 F(a/2, 4, 4) = 9.6045 46 126 93 39 134 67 F(a/2, 2, 3) = 16.0441 F(a/2, 6, 2) = 39.3315 F(a/2, 4, 3) = 9.12 G(a, 3, 4) = 0.7574 x12=x2 (α 2, 4) = 0.4844 x22 x 2 (1-a2, 4) = 11.1433 T(α, 5) = 1.92 33 133 95

Table 2 X Z 52 124 79 69 137 83 For Table 2, determine the confidence intervals of: 1. The mathematical expectation. 2. The variance. 3. The variation of the input quantity. Table values: a = 0.05 T(a/2, v= 1) = 12.7062 T(a/2, v= 2) = 4.3027 T(a/2, v= 3) = 3.1825 T(a/2, v= 4) = 2.7765 T(a/2, v= 8) = 2.3060 F(a/2, 2, 2) = 39.0000 F(a/2, 3, 3) = 15.4392 F(a/2, 4, 4) = 9.6045 46 126 93 39 134 67 F(a/2, 2, 3) = 16.0441 F(a/2, 6, 2) = 39.3315 F(a/2, 4, 3) = 9.12 G(a, 3, 4) = 0.7574 x12=x2 (α 2, 4) = 0.4844 x22 x 2 (1-a2, 4) = 11.1433 T(α, 5) = 1.92 33 133 95

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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Table 2 X y Z 52 124 79 69 137 83 For Table 2, determine the confidence intervals of: 1. The mathematical expectation. 2. The variance. 3. The variation of the input quantity. Table values: a = 0.05 T(a/2, v= 1) = 12.7062 T(a/2, v = 2) = 4.3027 T(a/2, v= 3) = 3.1825 T(a/2, v= 4) = 2.7765 T(a/2, v = 8) = 2.3060 F(a/2, 2, 2) = 39.0000 F(a/2, 3, 3) = 15.4392 F(a/2, 4, 4) = 9.6045 46 126 93 39 134 67 F(a/2, 2, 3) = 16.0441 F(a/2, 6, 2) = 39.3315 F(a/2, 4, 3) = 9.12 G(a, 3, 4) = 0.7574 x12= x2(a2, 4) = 0.4844 x2 2 x 2 (1-a2, 4) = 11.1433 T(α, 5) = 1.92 33 133 95
Transcribed Image Text:Table 2 X y Z 52 124 79 69 137 83 For Table 2, determine the confidence intervals of: 1. The mathematical expectation. 2. The variance. 3. The variation of the input quantity. Table values: a = 0.05 T(a/2, v= 1) = 12.7062 T(a/2, v = 2) = 4.3027 T(a/2, v= 3) = 3.1825 T(a/2, v= 4) = 2.7765 T(a/2, v = 8) = 2.3060 F(a/2, 2, 2) = 39.0000 F(a/2, 3, 3) = 15.4392 F(a/2, 4, 4) = 9.6045 46 126 93 39 134 67 F(a/2, 2, 3) = 16.0441 F(a/2, 6, 2) = 39.3315 F(a/2, 4, 3) = 9.12 G(a, 3, 4) = 0.7574 x12= x2(a2, 4) = 0.4844 x2 2 x 2 (1-a2, 4) = 11.1433 T(α, 5) = 1.92 33 133 95
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