Suppose that X and Y are random variables with E(X) = 2, E(Y) = 5 and E(X") = 8, E(Y) = 30 and cov(2X - Y,4X-3Y) = -12, then cov(-5X - 3,2Y +4) is equal to: Hint: cov(ax + bY,cx+ dY) acV(X) + bdV(Y) + (be + ad)cov(X,Y) -120 O -59 -64

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Suppose that X and Y are random variables with E(X) 2 , E(Y) = 5 and E(x?) = 8,
E(Y?) = 30 and cov(2X – Y,4X – 3Y) = -12, then cov(-5X – 3,2Y + 4) is equal to:
Hint: cov(ax + bY,cX + dY) = acV(X) + bdV(Y) + (bc + ad)cov(X,Y)
O -120
O -59
O -64
O -30
Transcribed Image Text:Suppose that X and Y are random variables with E(X) 2 , E(Y) = 5 and E(x?) = 8, E(Y?) = 30 and cov(2X – Y,4X – 3Y) = -12, then cov(-5X – 3,2Y + 4) is equal to: Hint: cov(ax + bY,cX + dY) = acV(X) + bdV(Y) + (bc + ad)cov(X,Y) O -120 O -59 O -64 O -30
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