SITUATION. A fully continuous monolithic floor system consists of slab as shown. Use the ACI moment coefficient as provided by the code. -M (interior support)= - 12 +M (midspan) = 16 7.4000 3.4000 3.4000 3.0000 3.0000 Design data: Live load= 4 kPa Floor finish=1 kPa Ceiling load= 0.25 kPa fc'= 21 MPa fy 276 MPa Use 12 mm diameter as main reinforcement. Use 10 mm diameter as secondary reinforcement. Compute the minimum thickness of the slab. 110 mm 120 mm 90 mm 100 mm
SITUATION. A fully continuous monolithic floor system consists of slab as shown. Use the ACI moment coefficient as provided by the code. -M (interior support)= - 12 +M (midspan) = 16 7.4000 3.4000 3.4000 3.0000 3.0000 Design data: Live load= 4 kPa Floor finish=1 kPa Ceiling load= 0.25 kPa fc'= 21 MPa fy 276 MPa Use 12 mm diameter as main reinforcement. Use 10 mm diameter as secondary reinforcement. Compute the minimum thickness of the slab. 110 mm 120 mm 90 mm 100 mm
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:SITUATION. A fully continuous monolithic floor system consists of slab as shown. Use the ACI
moment coefficient as provided by the code.
-M (interior support)= -
+M (midspan) =
16
7.4000
3.4000
3.4000
3.0000
3.0000
Design data:
Live load= 4 kPa
Floor finish= 1 kPa
Ceiling load= 0.25 kPa
fc'= 21 MPa
fy= 276 MPa
Use 12 mm diameter as main reinforcement.
Use 10 mm diameter as secondary reinforcement.
Compute the minimum thickness of the slab.
110 mm
120 mm
90 mm
100 mm
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