SHOW CALCULATIONS) If the energy of a photon is 1.27 x 10-18 J, what is its wavelength in nm3

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**Question**: (SHOW CALCULATIONS) If the energy of a photon is 1.27 × 10^-18 J, what is its wavelength in nm?

**Answer**: 

To find the wavelength of a photon, we can use the relationship between energy (E), Planck's constant (h), and the speed of light (c). The equation is:

\[ E = \frac{hc}{\lambda} \]

where:
- E is the energy of the photon.
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \) J·s).
- \( c \) is the speed of light (\( 3.00 \times 10^8 \) m/s).
- \(\lambda \) is the wavelength.

Rearranging the equation to solve for the wavelength (\(\lambda\)):

\[ \lambda = \frac{hc}{E} \]

Substituting the given values:

\[ \lambda = \frac{(6.626 \times 10^{-34} \text{ J·s}) \times (3.00 \times 10^8 \text{ m/s})}{1.27 \times 10^{-18} \text{ J}} \]

First, calculate the numerator:

\[ 6.626 \times 10^{-34} \text{ J·s} \times 3.00 \times 10^8 \text{ m/s} = 1.9878 \times 10^{-25} \text{ J·m} \]

Now, divide by the energy:

\[ \lambda = \frac{1.9878 \times 10^{-25} \text{ J·m}}{1.27 \times 10^{-18} \text{ J}} \approx 1.565 \times 10^{-7} \text{ m} \]

Converting meters to nanometers (1 m = \(10^9\) nm):

\[ \lambda = (1.565 \times 10^{-7} \text{ m}) \times (10^9 \text{ nm/m}) = 156.5 \text{ nm} \]

Therefore, the wavelength of the photon is approximately 156.5 nm.
Transcribed Image Text:**Question**: (SHOW CALCULATIONS) If the energy of a photon is 1.27 × 10^-18 J, what is its wavelength in nm? **Answer**: To find the wavelength of a photon, we can use the relationship between energy (E), Planck's constant (h), and the speed of light (c). The equation is: \[ E = \frac{hc}{\lambda} \] where: - E is the energy of the photon. - \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \) J·s). - \( c \) is the speed of light (\( 3.00 \times 10^8 \) m/s). - \(\lambda \) is the wavelength. Rearranging the equation to solve for the wavelength (\(\lambda\)): \[ \lambda = \frac{hc}{E} \] Substituting the given values: \[ \lambda = \frac{(6.626 \times 10^{-34} \text{ J·s}) \times (3.00 \times 10^8 \text{ m/s})}{1.27 \times 10^{-18} \text{ J}} \] First, calculate the numerator: \[ 6.626 \times 10^{-34} \text{ J·s} \times 3.00 \times 10^8 \text{ m/s} = 1.9878 \times 10^{-25} \text{ J·m} \] Now, divide by the energy: \[ \lambda = \frac{1.9878 \times 10^{-25} \text{ J·m}}{1.27 \times 10^{-18} \text{ J}} \approx 1.565 \times 10^{-7} \text{ m} \] Converting meters to nanometers (1 m = \(10^9\) nm): \[ \lambda = (1.565 \times 10^{-7} \text{ m}) \times (10^9 \text{ nm/m}) = 156.5 \text{ nm} \] Therefore, the wavelength of the photon is approximately 156.5 nm.
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