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se 2. The phasor of an AC voltage is given as V, -10-10V. Assuming that co= 5 rad/sec. this voltage in the time-domain is: ((a))v (1)=10cos(5t-45") V (b) v. (1)-10√ √2cos(51) V (c) v. (1)-10sin(5r) V (d) x.(0)=10√√2cos(51-45°) V

se 2. The phasor of an AC voltage is given as V, -10-10V. Assuming that co= 5 rad/sec. this voltage in the time-domain is: ((a))v (1)=10cos(5t-45") V (b) v. (1)-10√ √2cos(51) V (c) v. (1)-10sin(5r) V (d) x.(0)=10√√2cos(51-45°) V

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se 2. The phasor of an AC voltage is given as V, -10-10V. Assuming that = 5 rad/sec, this voltage in the time-domain is: ((a))v. (1)-10cos(51-45°) V (b) v (t)=10√2cos(5r) V (c) v. (1)-10sin(51) V (d) v (t)=10√2cos(51-45°) V
Transcribed Image Text:se 2. The phasor of an AC voltage is given as V, -10-10V. Assuming that = 5 rad/sec, this voltage in the time-domain is: ((a))v. (1)-10cos(51-45°) V (b) v (t)=10√2cos(5r) V (c) v. (1)-10sin(51) V (d) v (t)=10√2cos(51-45°) V
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