Asap. Please continue the solution SAMPLE PROBLEM 2:Assume that AE are equal for each rodRegd: Internal forces for member AB, CD, EFE Fy =0 +TAB + TCD + TEF = 15 kNBDFE Mc = 00.5 mTABTCDTEFESEF-0.4 m-02 m0.2 mO OCDỐCD - 8EFАВEF0.4mАВ0.8m0,4 m15 kN1/2 6 АВ + 1/26 EF%3DCDТАв (0.5)Tco(0,5)TEF (0.5)) +1/2AEAÉAE2 TAB+ 1/2 TEFTCD%3D2.3.

Given Data: Length of the beam, L=0.8 m

SAMPLE PROBLEM 2: Assume that AE are equal for each rod Reqd: Internal forces for member AB, CD, EF E Fy =0 + TAB + TcD + TEF = 15 kN B DE F Σ Mc - 0 0.5 m TAB TcD TEF E SEF OCD - SEF -0.4 m- CD-8, 0.2 m0.2 m O OCD AB EF 0.4m 0.8m 0,4 m AB V15 kN 1/2 б дв + 1/2 6 EF °CD %3D Tco(0,5) TEF (0.5) ) +1/2 AE ТАв (0,5) AE AÉ 3 2 TAB + 1/2 TEF TCD %3D 1. 2

SAMPLE PROBLEM 2: Assume that AE are equal for each rod Reqd: Internal forces for member AB, CD, EF E Fy =0 + TAB + TcD + TEF = 15 kN B DE F Σ Mc - 0 0.5 m TAB TcD TEF E SEF OCD - SEF -0.4 m- CD-8, 0.2 m0.2 m O OCD AB EF 0.4m 0.8m 0,4 m AB V15 kN 1/2 б дв + 1/2 6 EF °CD %3D Tco(0,5) TEF (0.5) ) +1/2 AE ТАв (0,5) AE AÉ 3 2 TAB + 1/2 TEF TCD %3D 1. 2

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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