Exercise 6• If the system in Example 8 has line transmission with impedance 10+j120, determine the phase current.for intnenal cimdarion anlye 202177 EXAMPLE 8 : balanced A-Y systemA balanced abc-sequence delta-connected source Vine = 210 V. Is connectedto a Y-connected balanced load 40+ j25 O per phase.1. Calculate the phase currents and use Vah as reference.2. Draw the phasor diagramScanned with CamScannerSolutionThe load impedance isZ, - 40 + 25 = 47.17/32 1and the source voltage isV- 210/0 vWhen the A-connected source is transformed to a Y-connected source,-30 = 121.2/-30° VThe line curTrents areV 121.2/-3047.12/321, - L/-120 - 257/-178 AL-L/120 = 257/58 A257/-62'A+hich are the same as the plh.e currents

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Answered: rmine the phase current.

Engineering

Electrical Engineering

rmine the phase current.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Single Phase AC Circuit

Alternating Current (AC) is a type of electric power in which the electric current changes, both in magnitude and direction, at regular intervals. This AC Circuits can deliver power in either a Single Phase system or a Three Phase system.

Question

Exercise 6
• If the system in Example 8 has line transmission with impedance 10
+j120, determine the phase current.
for intnenal cimdarion anlye 2021
77

EXAMPLE 8 : balanced A-Y system
A balanced abc-sequence delta-connected source Vine = 210 V. Is connected
to a Y-connected balanced load 40+ j25 O per phase.
1. Calculate the phase currents and use Vah as reference.
2. Draw the phasor diagram
Scanned with CamScanner
Solution
The load impedance is
Z, - 40 + 25 = 47.17/32 1
and the source voltage is
V- 210/0 v
When the A-connected source is transformed to a Y-connected source,
-30 = 121.2/-30° V
The line curTrents are
V 121.2/-30
47.12/32
1, - L/-120 - 257/-178 A
L-L/120 = 257/58 A
257/-62'A
+hich are the same as the plh.e currents

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