1, 2 and 3 are right. I just need help with 4, 5 and 6 Red light is incident in air on a 30° -60° - 90 ° prism as shown. The incident beam isdirected at an angle of ₁ = 40.20 with respect to the horizontal and enters the prismat a height h = 20 cm above the base. The beam leaves the prism to the air at adistance d = 54.2 along the base as shown.45.661.3630⁰1) What is 2, the angle the beam in the prism makes with the horizontal axis?71.9ddegrees Submit2) What is n, the index of refraction of the prism for red light?dviolet dSubmitSubmit023) What is 3, the angle the transmitted beam makes with the horizontal axis?hdegrees Submit03degrees Submit(+)4) What is 41,max, the maximum value of 1 for which the incident beam experiencestotal internal reflection at the horizontal face of the prism?degrees Submit++5) The red beam is now replaced by a violet beam that is incident at the same angle 1and same height h. The prism has an index of refraction nviolet = 1.46 for violetlight. Compare dviolet, the exit distance for violet light, to d, the exit distance for redlight.++6) Suppose now that the violet beam is incident at height h, but makes an angle 41,v=60⁰ with the horizontal. What is 43,v, the angle the transmitted beam makes withthe horizontal axis?

4. Solution: Applying snell law at the incident interface of light. sinφ1=μsinr1since, φ1+r1=30°For…

Answered: Red light is incident in air on a 30°…

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Red light is incident in air on a 30° -60°-90° prism as shown. The incident beam is directed at an angle of ₁ = 40.20 with respect to the horizontal and enters the prism at a height h = 20 cm above the base. The beam leaves the prism to the air at a distance d = 54.2 along the base as shown.