Draw symbol table for the following code using separate chaining approach. Assume size of the table is 10. Show how the table evolves at each statement. You can calculate hash value using the hash() function provided underneath:public class CC {int a;public void m(int a) {char c='B';{double d=0.0;}}} //end CC class public int hash( String k ) { int value = 0; for( int i=0; i<k.length(); i++ ) { value = value + (int)k.charAt( i ); } return value % 10;} //end HASH() functionHint: A-Z ranges 65-90 and a-z ranges 97-122. Hence identifier A will have has value 5, B will have 6, and similarly identifier AB will have 1 and so on.

import java. i o. * ; import java.util.scanner; class CC { public static int…

Answered: raw symbol table for the following code…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Draw symbol table for the following code using separate chaining approach. Assume size of the table is 10. Show how the table evolves at each statement. You can calculate hash value using the hash() function provided underneath:

public class CC {
int a;
public void m(int a) {
char c='B';
{
double d=0.0;
}
}
} //end CC class

public int hash( String k ) {

int value = 0;

for( int i=0; i<k.length(); i++ ) {

value = value + (int)k.charAt( i );

}

return value % 10;

} //end HASH() function

Hint: A-Z ranges 65-90 and a-z ranges 97-122. Hence identifier A will have has value 5, B will have 6, and similarly identifier AB will have 1 and so on.

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