Question three: Chi square You mate wildtype (ete ) with ebony ( ee), after more than a month you got the F2, the number of the offspring was 100, 78 of them were wildtype and 22 were ebony. Is there a significant difference between observed and expected results? Calculate chi square, then reject or accept the null and remember that the cut off value of p-value is 0.05. Phenotype WT Ebony Total Observed 78 22 Expected 100 d.f. 995 990 .975 950 900 500 .100 .050 .025 010 .005 .00+ .00+ .00+ .00+ .02 45 2.71 3.84 5.02 6.63 7.88 .01 .02 05 .10 21 1.39 4.61 5.99 7.38 9.21 10.60 3. .07 22 35 58 2.37 6.25 7.81 9.35 11.34 12.84

Human Anatomy & Physiology (11th Edition)
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Question three: Chi square
You mate wildtype (ete) with ebony ( ee), after more than a month you got the F2, the
number of the offspring was 100, 78 of them were wildtype and 22 were ebony. Is there
a significant difference between observed and expected results?
Calculate chi square, then reject or accept the null and remember that the cut off value
of p-value is 0.05.
Phenotype
WT
Ebony
Total
Observed
78
Expected
22
100
d.f.
995
.990
975
.950
900
500
100
.050
.025
.010
.005
.00+
.00+
.00+
.00+
.02
45
2.71
3.84
5.02
6.63
7.88
2
.01
.02
.05
.10
21
1.39
4.61
5.99
7.38
9.21
10.60
3
.07
11
22
35
58
2.37
6.25
7.81
9.35
11.34
12.84
Transcribed Image Text:Question three: Chi square You mate wildtype (ete) with ebony ( ee), after more than a month you got the F2, the number of the offspring was 100, 78 of them were wildtype and 22 were ebony. Is there a significant difference between observed and expected results? Calculate chi square, then reject or accept the null and remember that the cut off value of p-value is 0.05. Phenotype WT Ebony Total Observed 78 Expected 22 100 d.f. 995 .990 975 .950 900 500 100 .050 .025 .010 .005 .00+ .00+ .00+ .00+ .02 45 2.71 3.84 5.02 6.63 7.88 2 .01 .02 .05 .10 21 1.39 4.61 5.99 7.38 9.21 10.60 3 .07 11 22 35 58 2.37 6.25 7.81 9.35 11.34 12.84
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