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- Suppose IQ scores were obtained for 20 randomly selected sets of twins. The 20 pairs of measurements yield x = 102.36, y = 104.7, r=0.949, P-value = 0.000, and y = 0.27 + 1.02x, where x represents the IQ score of the twin born first. Find the best predicted value of y given that the twin born first has an IQ of 99? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is (Round to two decimal places as needed.)A nutrition expert claims that the average American is overweight: To test his claim, a random sample of 25 Americans was selected, and the difference between each person's actual weight and idea weight was calculated. For this data, we have = 16 and 8 = 28.4. Is there sufficient evidence to conclude that the expert's claim is true? Carry out a hypothesis test at a 8% significance level. Hint: Pay attention to the variable being measured: the difference between actual weight and ideal. A positive value indicates that the person is overweight. A. The value of the standardized test statistic (give to 3 decimal places): B. The p-value is (give to 4 decimal places): C. Your decision for the hypothesis test: O A. Reject Ho- OB. Reject Ha C. Do Not Reject Ha- O D. Do Not Reject Ho- Eif a researcher concludes that cereal color has no effect on amount consumed but the researcher was wrong in this conclusion which of the following best represents his decision? correct decision, type 1 error, type 2 error, or type 3 error
- The relationship between the independent variable (IV) and the dependent variable (DV) is likely to be mediated by a third variable (MV). With regard to the statement above, which of the following is most likely to be correct? A IV = Students’ performance (i.e., marks) in the formative assessment; DV = Students’ performance (i.e., marks) in the summative assessment, and MV = Students’ level of comfort with the venue of the assessments B IV = Students’ performance (i.e., marks) in the summative assessment; DV = Students’ performance (i.e., marks) in the formative assessment, and MV = Students’ level of preparation for the assessments. C IV = Students’ performance (i.e., marks) in the formative assessment; DV = Students’ performance (i.e., marks) in the summative assessment, and MV = Students’ level of preparation for the assessments D IV = Students’ performance (i.e., marks) in the summative assessment; DV = Students’ performance (i.e., marks) in the formative assessment,…Steps 1,2, and threeSuppose IQ scores were obtained for 20 randomly selected sets of twins. The 20 pairs of measurements yield x= 103.44, y= 102.45, r 0.959, P-value = 0.000, and y =-9.9+ 1.09x, where x represents the IQ score of the %3D %3D twin born first. Find the best predicted value of y given that the twin born first has an IQ of 95? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is (Round to two decimal places as needed.)
- Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x=102.2, y=100.8, r=0.854, P-value=0.000, and y=24.13+0.75x, where x represents the IQ score of the wife. Find the best predicted value of y given that the wife has an IQ of 95? Use a significance level of 0.05. LOADING... Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is nothing.An article reported the results of a peer tutoring program to help children learn to read. In the experiment, the children were randomly divided into two groups: the experimental group received peer tutoring along with regular instruction, and the control group received regular instruction with no peer tutoring. There were n1 = n2 = 36 children in each group. The Gates-MacGintie Reading Test was given to both groups before instruction began. For the experimental group, the mean score on the vocabulary portion of the test was x1 = 344.5, with sample standard deviation s1 = 45.5. For the control group, the mean score on the same test was x2 = 334.3, with sample standard deviation s2 = 48.5. Use a 10% level of significance to test the hypothesis that there was no difference in the vocabulary scores of the two groups before the instruction began. (a) What is the level of significance?State the null and alternate hypotheses. H0: ?1 = ?2; H1: ?1 > ?2H0: ?1 = ?2; H1: ?1 < ?2 H0: ?1 ≠…QUESTION 3 Significance level (a) aims to control which type(s) of error? O Type I error O Type Il error O Type I and Type II error O Significance level is not related to controlling for error. QUESTION 4 forror?
- Need help writing a null hypothesis for the bivariate relationship shown in the SPSS output.After the measles outbreak, the barangay captain of Big Rock wanted to assess the satisfaction of the residents to his actions during the outbreak. He then obtained a random sample of 5 residents per block (Block 1 to Block 5) and asked them their satisfaction (1 – very dissatisfied, 2- dissatisfied, 3- satisfied, 4- very satisfied). He wanted to know if the satisfaction of his residents differs across blocks. i. True or False: We should test the normality of responses per blocks before we proceed with the test of hypothesis on comparing these responses across blocks. ii. The appropriate alternative hypothesis in symbols is? a) At least one µi # µj, for izj, i,j=1,2,3,4,5 b) At least one Mdi + Mdj, for i#j, i,j=1,2,3,4,5 c ) μ1 μ2-μ3-μ4 μ5 d) Md1= Md2 = Md3 = Md4 = Md5 iii. Suppose the p-value of appropriate test is 0.0013, at 5% level of significance, we have evidence to say that at least one block has a different average a) Insufficient; measles outbreak b) Sufficient; measles…please answer questions B,C,F
