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Question 6) Spherical particles having a density of 5.4 g/cm' falling in water at 25 °C reaches the terminal velocity value of 0.015 m/s. Assume that there is no turbulent flow and that there are no collisions or interactions between the particles. Calculate the Stoke's diameter of the particles using the data and the Stoke's equation given below. (% 15) d (H,O at 25 °C) =1.0 g/cm n(H,O at 25 °C) = 0.8904mPa.s g = 9.81m/s 1/2 18ην x%3D |(ds-d)g

Question 6) Spherical particles having a density of 5.4 g/cm' falling in water at 25 °C reaches the terminal velocity value of 0.015 m/s. Assume that there is no turbulent flow and that there are no collisions or interactions between the particles. Calculate the Stoke's diameter of the particles using the data and the Stoke's equation given below. (% 15) d (H,O at 25 °C) =1.0 g/cm n(H,O at 25 °C) = 0.8904mPa.s g = 9.81m/s 1/2 18ην x%3D |(ds-d)g

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question 6) Spherical particles having a density of 5.4 g/cm² falling in water at 25 °C reaches the terminal velocity value of 0.015 m/s. Assume that there is no turbulent flow and that there are no collisions or interactions between the particles. Calculate the Stoke's diameter of the particles using the data and the Stoke's equation given below. (% 15) d (H,O at 25 °C) =1.0 g/cm n(H,0 at 25 °C) = 0.8904mPa.s g = 9.81 m/s 1/2 18ην =x (ds-d)g
Transcribed Image Text:Question 6) Spherical particles having a density of 5.4 g/cm² falling in water at 25 °C reaches the terminal velocity value of 0.015 m/s. Assume that there is no turbulent flow and that there are no collisions or interactions between the particles. Calculate the Stoke's diameter of the particles using the data and the Stoke's equation given below. (% 15) d (H,O at 25 °C) =1.0 g/cm n(H,0 at 25 °C) = 0.8904mPa.s g = 9.81 m/s 1/2 18ην =x (ds-d)g
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