Question 1: Solve the portal frame by moment distribution method 4 w Lm w= 240 kN 6 w L= 12.8 m 1.2 Lm Lm Lm Data for Problem 1 The members are made of Reinforced concrete. Concrete modulus of elasticity would be calculated as E = 57000f.. where the compressive strength of concrete to be taken as 6000 psi. The value of E may be converted into Sl units. The cross-section dimensions of the left and right columns are 600 mm X 600 mm and the middle column is 800 mm X 800 mm. The top and middle horizontal members are 400 mm X 900 mm and 400 mm X 1000 mm respectively. Analyze the frame by the moment distribution method. Calculate reactions and draw the shear force and bending moment diagrams.
Question 1: Solve the portal frame by moment distribution method 4 w Lm w= 240 kN 6 w L= 12.8 m 1.2 Lm Lm Lm Data for Problem 1 The members are made of Reinforced concrete. Concrete modulus of elasticity would be calculated as E = 57000f.. where the compressive strength of concrete to be taken as 6000 psi. The value of E may be converted into Sl units. The cross-section dimensions of the left and right columns are 600 mm X 600 mm and the middle column is 800 mm X 800 mm. The top and middle horizontal members are 400 mm X 900 mm and 400 mm X 1000 mm respectively. Analyze the frame by the moment distribution method. Calculate reactions and draw the shear force and bending moment diagrams.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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