Quantity Trial 1 Trial 2 Trial 3 MNAOH (exact concentration) 1.189 1.189 1.189 Vinitial buret reading = Vi ml 1.16 29.31 15.03 Vfinal buret reading = Vf ml 15.02 38.06 28.99 Vep = VNAOH added = Vf - Vi ml Vep = VNAOH in L L %3D moles NaOH = MNAOH x VNAOH mol moles AA = moles NaOH mol Vsample = Vacid L Actual molarity of AA Average molarity of AA for Discarding Outlying Results: If the deviation of the outlying value is greater than four times the average deviation, the sample potentially can be discarded. acetic acid molar mass 60.05 g/mol vinegar density 1.05 g/mL
Quantity Trial 1 Trial 2 Trial 3 MNAOH (exact concentration) 1.189 1.189 1.189 Vinitial buret reading = Vi ml 1.16 29.31 15.03 Vfinal buret reading = Vf ml 15.02 38.06 28.99 Vep = VNAOH added = Vf - Vi ml Vep = VNAOH in L L %3D moles NaOH = MNAOH x VNAOH mol moles AA = moles NaOH mol Vsample = Vacid L Actual molarity of AA Average molarity of AA for Discarding Outlying Results: If the deviation of the outlying value is greater than four times the average deviation, the sample potentially can be discarded. acetic acid molar mass 60.05 g/mol vinegar density 1.05 g/mL
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
- Fill in the blanks.
- Calculate the Average molarity (M) of Acetic acid in vinegar, using the following data.
- Calculate the mass percent of acetic acid in vinegar, using your average Acetic acid concentration (M) from the above result.
Table 2. Data for titration of 20.00 mL of vinegar with approximately 1.2 M NaOH.

Transcribed Image Text:Quantity
Trial 1
Trial 2
Trial 3
MNAOH (exact concentration)
M
1.189
1.189
1.189
Vinitial buret reading = Vi
ml
1.16
29.31
15.03
%3D
Vfinal buret reading = Vf
ml
15.02
38.06
28.99
Vep = VNAOH added = Vf - Vi
ml
Vep = VNAOH in L
L
moles NaOH = MNAOH x VNAOH
mol
moles AA = moles NaOH
mol
Vsample = Vacid
L
Actual molarity of AA
M
Average molarity of AA
for Discarding Outlying Results: If the deviation of the outlying value is greater than four times the
average deviation, the sample potentially can be discarded.
M
acetic acid molar mass
vinegar density
60.05 g/mol
1.05 g/mL
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