Q.1.1.1 Calculate the standard deviation of the difference between the mean opinion scores of gas ovens and electric ovens. Q.1.1.2 The analyst concluded that there was 50% probability that the sample mean of opinion scores of gas ovens is smaller than that of electric ovens. He used z-transformations and got z = -3.9. Calculate the z value using information in the table to check if the value of -3.9 used by the analyst was correct.
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Q.1.1 |
Consumer testing services compared public opinion on gas ovens and electric ovens. They asked participants to rate their opinions using a scale from 1 to 10. A random sample of 220 households were interviewed. The Mean Gas Ovens mean7.45 standars deviation3.32 sample size220 Electric Ovens mean8.85 standard deviation4.14 sample size220 |
Q.1.1.1
Calculate the standard deviation of the difference between the mean opinion scores of gas ovens and electric ovens.
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Q.1.1.2 |
The analyst concluded that there was 50% probability that the sample mean of opinion scores of gas ovens is smaller than that of electric ovens. He used z-transformations and got z = -3.9. Calculate the z value using information in the table to check if the value of -3.9 used by the analyst was correct. |
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