Problem 1: A reverse curve has a radius of the curve passing through the P.C. equal to 200m and that of the second curve passing through the P.T. is 460 m. long. If the central angle of curve is 12. a.) Find the perpendicular distance between the two parallel tangents. b.) If the stationing of the P.C. is 2+360.20, find the stationing of the P.R.C. c.) Find the stationing of the P.T. 2+360.20 P.C. R3=460 R,=200 PT.

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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Problem 1:
A reverse curve has a radius of the curve passing through the P.C. equal to 200m and that of
the second curve passing through the P.T. is 460 m. long. If the central angle of curve is 12.
a.) Find the perpendicular distance between the two parallel tangents.
b.) If the stationing of the P.C. is 2+360.20, find the stationing of the P.R.C.
c.) Find the stationing of the P.T.
2+360.20
P.C.
R3=460
R=200|
PT.
Transcribed Image Text:Problem 1: A reverse curve has a radius of the curve passing through the P.C. equal to 200m and that of the second curve passing through the P.T. is 460 m. long. If the central angle of curve is 12. a.) Find the perpendicular distance between the two parallel tangents. b.) If the stationing of the P.C. is 2+360.20, find the stationing of the P.R.C. c.) Find the stationing of the P.T. 2+360.20 P.C. R3=460 R=200| PT.
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