probability .9 if he passed the previous test and fails w test. Find the probability that a student passes two of Ist test=.6-7pessoad test = .9 fail-> 2nd=.!?
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![10. A student passes the first test with probability.6. For each additional test, a student passes with
probability .9 if he passed the previous test and fails with probability .7 if he failed the previous
test. Find the probability that a student passes two of the first three tests.
Ist test=.6 -7passo>
o fail-> Ind=?
P2 test =
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- board.com/webapps/discussionboard/do/message?action=create&do=create&postfirstedit=true&requestType-thread&course_id=_21308_1&nav=di. buy one ticket. Does the probadmity or winning une jackpot change because the jackpot is migner! (c) The probability of winning any prize is about 0.0402. Suppose you decide to buy five tickets. Use the binomial distribution to compute the probability of winning (any prize) at least once. Note: You will need to use the binomial formula. Carry at least three digits after the decimal. Figure 6-7 P OWE ********** Match 5 white balls + Powerball 5 white balls 4 white balls + Powerball 4 white balls 3 white balls + Powerball 3 white balls 2 white balls + Powerball 1 white ball + Powerball 0 white balls + Powerball Overall chance ofriesine R BALL Approximate Probability Prize 0.0000000034 0.000000085 0.00000109 0.000027 0.000069 0.00172 0.00143 0.01087 0.0261 00405 Click Save Draft to save a draft of this message. Click Submit to submit the post. Click Cancel…In screening for a certain disease, the probability that a healthy person wrongly gets a positive result is0.05. The probability that a diseased person wrongly gets a negative result is 0.002. The overall rate ofthe disease in the population being screened is 1%. If my test gives a positive result, what is theprobability I actually have the disease? ( dont hand writing solution)I need the answer quickly
- It is a probability question In CSE230, there were 2 assignments this semester. The probabilities that you would NOT get full marks in the first and second assignments are 0.55 and 0.62 respectively. Now, if you get full marks in the second assignment that makes your probability of getting full marks in the first assignment as 0.52. What is the probability of getting full marks in the second assignment given that you got full marks in the first assignment? unanswered In CSE230, there were 2 assignments this semester. The probabilities that you would NOT get full marks in the first and second assignments are 0.55 and 0.62 respectively. Now, if you get full marks in the second assignment that makes your probability of getting full marks in the first assignment as 0.52. What is the probability of getting full marks in the second assignment given that you got full marks in the first assignment? unansweredThe table summarizes results from 984 pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths Driver Pedestrian Intoxicated? Intoxicated? Yes No Yes 58 82 No 286 558 If one of the pedestrian deaths is randomly selected, find the probability that neither the pedestrian nor the driver was intoxicated. Please enter a decimal to 4 places. Probability =56.6
- A bag contains 2 red balls worth £3, 2 blue balls worth £2 and 5 green balls worth £0. You pick 1 ball out of the bag (without replacement). What the expected value of earnings from playing this game once (3 decimal places).Please solve it as soon as possibleNissa is randomly pulling the medical records of a hospital's patients and collecting the records of those who have multiple stays at this hospital. Assume that 27% of all patients who have ever stayed at this hospital have multiple stays. What is the probability that the first multiple stays patient record that Nissa comes across is the fourth one she pulls? Use a TI-83, TI-83 Plus, or TI-84 calculator to find the probability. • Round your answer to three decimal places.
- The table summarizes results from 988 pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths DriverIntoxicated? Pedestrian Intoxicated? Yes No Yes 48 77 No 217 646 If one of the pedestrian deaths is randomly selected, find the probability that both the pedestrian and the driver were intoxicated. Please enter a decimal to 4 places.Probability =The table summarizes results from 975 pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths DriverIntoxicated? Pedestrian Intoxicated? Yes No Yes 47 75 No 252 601 If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was not intoxicated but the driver was. Please enter a decimal to 4 places.Probability =
