pH graph for the 0.20 M strong base titration of 25.0 mL benzoic acid (0.150 M) is shown here. Acume the equivalence point was x ml., and the pH at the equivalence point is c. (Ka of benzoic acid = 6.46 x 105) Complete the following:(write final answer) A) The value of point x = ml B) Without any calculation, the pH for point C is more than C) The pH at point az D) The pH at point b= p X/2 We of 20 da the acid decreases?

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Question 20
pH graph for the 0.20 M strong base titration
of 25.0 mL benzoic acid (0.150 M) is shown
here. Asume the equivalence point was x
ml., and the pH at the equivalence point is c.
(Ka of benzoic acid = 6.46 x 105)
Complete the following:(write final answer)
X/2
We are 200
A) The value of
point x =
ml
B) Without any calculation, the pH for point C is more than_
C) The pH at point a =
D) The pH at point b=
E) Predict how the curve will behave when the Ka value of the acid decreases?
pl
Last saved 308:27 PM
Transcribed Image Text:Question 20 pH graph for the 0.20 M strong base titration of 25.0 mL benzoic acid (0.150 M) is shown here. Asume the equivalence point was x ml., and the pH at the equivalence point is c. (Ka of benzoic acid = 6.46 x 105) Complete the following:(write final answer) X/2 We are 200 A) The value of point x = ml B) Without any calculation, the pH for point C is more than_ C) The pH at point a = D) The pH at point b= E) Predict how the curve will behave when the Ka value of the acid decreases? pl Last saved 308:27 PM
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