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Analyze the given parameters before ticking the right answer * pOH = 3 [H+] = 4.2 x 10-3 [OH-] = 3.16 x 10-9 ACIDIC O BASIC O NEUTRAL O

Analyze the given parameters before ticking the right answer * pOH = 3 [H+] = 4.2 x 10-3 [OH-] = 3.16 x 10-9 ACIDIC O BASIC O NEUTRAL O

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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* Analyze the given parameters before ticking the right answer * pOH = 3 [H+] = 4.2 x 10-3 [OH-] = 3.16 x 10-9 Blue litmus paper remains blue pH = 7.15 + log [0.25]/[0.50] pH = pka + log [0.33]/[0.11]; (Ka = 6.3096 x 10-8) [OH-] = 2.78 x 10-4 Blue litmus paper changes to red % ionization of 34 relative to pka value A litmus paper turning violet ACIDIC O O O ο ο ο ( O O BASIC O ос O DO ( O O O NEUTRAL O O O O O
Transcribed Image Text:* Analyze the given parameters before ticking the right answer * pOH = 3 [H+] = 4.2 x 10-3 [OH-] = 3.16 x 10-9 Blue litmus paper remains blue pH = 7.15 + log [0.25]/[0.50] pH = pka + log [0.33]/[0.11]; (Ka = 6.3096 x 10-8) [OH-] = 2.78 x 10-4 Blue litmus paper changes to red % ionization of 34 relative to pka value A litmus paper turning violet ACIDIC O O O ο ο ο ( O O BASIC O ос O DO ( O O O NEUTRAL O O O O O
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pH = 7.15 + log [0.25]/[0.50]

pH = pKa + log [0.33]/[0.11]; (Ka = 6.3096 x 10-8)

[OH-] = 2.78 x 10-4

% ionization of 34 relative to pKa value

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