PH 12- 10 8- 6 2- PM 1 at the start due to 0.1M HCI (strong monoprotic acid) 0 5 O end point, pH of 7 Adding 0.1M NaOH to 25 mL of 0.1M HCI 10 15 20 25 30 35 40 Volume of alkali added/cm3 equivalence point, pH of 7 end point, 25.0 mL equivalence point, 25.0 mL

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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MN10.

 

25. The point where the hydroxide ion concentration is equal to the
hydronium ion concentration for the titration represented by the graph
below is called the
and is
PH
strong acid (HCI) v. strong base (NaOH)
14
12
10-
6-
2-
pH 1 at the start
due to 0.1M HCI
(strong
monopratic acid)
0
5
10 15 20 25 30 35 40
Adding 0.1M NaOH
to 25 mL of 0.1M HCI
Volume of alkali added/cm3
end point, pH of 7
equivalence point, pH of 7
end point, 25.0 mL
equivalence point, 25.0 mL
Transcribed Image Text:25. The point where the hydroxide ion concentration is equal to the hydronium ion concentration for the titration represented by the graph below is called the and is PH strong acid (HCI) v. strong base (NaOH) 14 12 10- 6- 2- pH 1 at the start due to 0.1M HCI (strong monopratic acid) 0 5 10 15 20 25 30 35 40 Adding 0.1M NaOH to 25 mL of 0.1M HCI Volume of alkali added/cm3 end point, pH of 7 equivalence point, pH of 7 end point, 25.0 mL equivalence point, 25.0 mL
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