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PG₁ = 15 KW Step2 b) Part A The single-line diagram of the hole system will be, VG₁ IGL = -WW 1.4 PG₁ √3VLL COS 15×10³ √3x460x0.8 j1.6 www m 0.8 jl The active power supplied to the generator will be, PG1 √3VLLIL COS so the current supplied by generator 1 will be, IG₁ 162 - 36.86 =23.533 – 36.86° A On applying KVL in the above figure will be, G2

PG₁ = 15 KW Step2 b) Part A The single-line diagram of the hole system will be, VG₁ IGL = -WW 1.4 PG₁ √3VLL COS 15×10³ √3x460x0.8 j1.6 www m 0.8 jl The active power supplied to the generator will be, PG1 √3VLLIL COS so the current supplied by generator 1 will be, IG₁ 162 - 36.86 =23.533 – 36.86° A On applying KVL in the above figure will be, G2

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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PG₁ = 15 KW Step2 b) Part A The single-line diagram of the hole system will be, V-460/20 VG₁ IGI = -WW m 1.4 j1.6 PG₁ √3VLL COS 15×10³ √3×460×0.8 The active power supplied to the generator will be, PG1 √3VLLIL COS so the current supplied by generator 1 will be, IG₁ www m 0.8 jl - 36.86 =23.533 – 36.86° A On applying KVL in the above figure will be, V₁ + IG₁ Z1 − Vg₁=0 162 VL=VG₁ - IG₁Z₁ 460 22 592 G2 100
Transcribed Image Text:PG₁ = 15 KW Step2 b) Part A The single-line diagram of the hole system will be, V-460/20 VG₁ IGI = -WW m 1.4 j1.6 PG₁ √3VLL COS 15×10³ √3×460×0.8 The active power supplied to the generator will be, PG1 √3VLLIL COS so the current supplied by generator 1 will be, IG₁ www m 0.8 jl - 36.86 =23.533 – 36.86° A On applying KVL in the above figure will be, V₁ + IG₁ Z1 − Vg₁=0 162 VL=VG₁ - IG₁Z₁ 460 22 592 G2 100
Problem 7. Two three-phase generators supply a three-phase load through separate three-phase lines. The load absorbs 30 kW at 0.8 power factor lagging. The line impedance is (1.4 +j1.6) per phase between generator G1 and the load, and (0.8+j1) per phase between generator G2 and the load. If generator G1 supplies 15 kW at 0.8 power factor lagging, with a terminal voltage of 460 V line-to- line, determine: a) The voltage at the load terminals. b) The voltage at the terminals of generator G2. c) The real and reactive power supplied by generator G2.
Transcribed Image Text:Problem 7. Two three-phase generators supply a three-phase load through separate three-phase lines. The load absorbs 30 kW at 0.8 power factor lagging. The line impedance is (1.4 +j1.6) per phase between generator G1 and the load, and (0.8+j1) per phase between generator G2 and the load. If generator G1 supplies 15 kW at 0.8 power factor lagging, with a terminal voltage of 460 V line-to- line, determine: a) The voltage at the load terminals. b) The voltage at the terminals of generator G2. c) The real and reactive power supplied by generator G2.
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