Olaf is resting on an inclined surface while being attached to a cable and a frictionless pulley as shown on the diagram. Anna, behind the plane, pulls Olaf by force F. Upon pulling, he slides at a distance of A, parallel to the surface in 20.0 s under constant acceleration.

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Q: 5.00-m ramp to a height h = 3.00 m.

A: The questions are answered below

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A: Drawing Free body diagram of the wheelbarrow We know that workdone W=F×D×cos(θ)…

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Q: MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A tension force of 145 N inclined at 25.0° above the…

A: a. work done by the tension force is  WF=Fcosθd                                 1=145 Ncos25°4.6…

Q: 1] A 20kg mass hangs at rest at end of a pendulum rope. Assume that you push it up at 0.6m above…

A: Hello. Since your question has multiple sub-parts, we will solve the first three sub-parts for you.…

Q: Determine the force value if work done is equal to 20 J and displacement is 8 m

A: Given data:  Work done (W) = 20 J Displacement (d) = 8 m Required: Force (F)

Q: Determine the force value if work done is equal to 20 J and displacement is 8 m

A: given-     Work done = 20 J,    displacement = 8 m

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A: According to Hook's law F = kx Potential energy of spring = (1/2) kx2

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A: Given information: Work is done on an object by applying a force.

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A: The area under force distance graph is equal to the work done by the force,

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A: Given :- graph between Fx-X   mass of object m=3kg

Q: mass m suspended from a spring elongated with respect to its equilibrium position O, is released…

A: Spring constant = k mass = m Initial displacement from equilibrium position = a final position = 'h'…

Q: Do not skip this

A: Given that-Mass of the sled, m= 70 kgLength of the plane, L= 80 mAngle of inclination of the plane…

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A: applied force = 8i^ + 5j^ N displacement = 9 m to right = 9 i^ m

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Q: y (m) C (5.00, 5.00) B x (m) A The force acting on a part F = 2(xy) î

A: Given: Force acting on the particle, F = 2(xy) Î

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Q: Consider the skateboarder in the Figure. If she has a mass of 55 kg, an initial velocity of 20 m/s,…

A: Mass = 55 kg  Speed at bottom = 20 m/s  Speed at top = 12 m/s  Height = 5 m

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A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

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Q: how would you solve this only using work/power formulas and PE/KE formulas?

A: