MY QUESTION IS WHY IS IT 4 ON THE UNDERLINED ONE?? I DON'T UNDERSTAND 1.20mA1. 80 m0.9o mStep-1Fon memberABRBVRBHLength, LAB: 1:2? +1:2²= l·69m1:20mWABくRAHAweight, WAB = 1:69x 3= 5.07 KN%3DRAVE MA = OFBD ol meer AB+ 4 RBV4 RBH= a WAB X O6ReH + Rev =5.07 x o.6ci)6.761 KN.RBVFor step-2 For menmber BCRBHLngthLB -Lergth Lec山10-とこて31t16.0Beくmiseight, wec2.01 X 3 = 6.0 3 KN0-45%3DRCHEMc -k09mRev1.8 RBH = 045 WBc + o9RFBD of mer Bc1-8 RRH - 0 9RBV = 0.45 x 6.632.71こ1.8 RBH - 019 RBY2 PBHRBVci)= 3.01..... PROBLEM 2.A structure shown in the figure weighs 3 kN/m each member supported by hinges at A andC. Calculate the maximum shearing stress in point A if the diameter of the pin is 15 mmassuming the it is a single shear.B1.20 m1.80 mA-1.20 m--0.90 m

Since the perpendicular distance of RBH and RBV from point A is 1.2 m each, hence moment about A…

Answered: MY QUESTION IS WHY IS IT 4 ON THE…

Engineering

Civil Engineering

MY QUESTION IS WHY IS IT 4 ON THE UNDERLINED ONE?? I DON'T UNDERSTAND

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

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MY QUESTION IS WHY IS IT 4 ON THE UNDERLINED ONE?? I DON'T UNDERSTAND

1.20m
A
1. 80 m
0.9o m
Step-1
Fon member
AB
RBV
RBH
Length, LAB: 1:2? +1:2²= l·69m
1:20m
WAB
く
RAHA
weight, WAB = 1:69x 3
= 5.07 KN
%3D
RAV
E MA = O
FBD ol meer AB
+ 4 RBV
4 RBH
= a WAB X O6
ReH + Rev =
5.07 x o.6
ci)
6.761 KN.
RBV
For step-2 For menmber BC
RBH
LngthLB -
Lergth Lec
山10-とこて31t16.0
Be
くm
iseight, wec
2.01 X 3 = 6.0 3 KN
0-45
%3D
RCH
EMc -
k09m
Rev
1.8 RBH = 045 WBc + o9R
FBD of mer Bc
1-8 RRH - 0 9RBV = 0.45 x 6.63
2.71
こ
1.8 RBH - 019 RBY
2 PBH
RBV
ci)
= 3.01
.....

PROBLEM 2.
A structure shown in the figure weighs 3 kN/m each member supported by hinges at A and
C. Calculate the maximum shearing stress in point A if the diameter of the pin is 15 mm
assuming the it is a single shear.
B
1.20 m
1.80 m
A
-1.20 m-
-0.90 m

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