). A circular bar of 2 m length has a diameter 100 mm (E=200 Gpa, v=0.32,a = 11.7µ/c°). The bar's left end is built into a rigid wall and a gap of 0.5 mmexists between right wall and right end of the bar prior to an increase in thtemperature. The temperature of the bar is increased uniformly by 80 c°.Determine the average axial stress and change in the diameter of the bar15

Given : L = 2m = 2000mm D = 100mm μ = 0.32 α=11.7×10-6/°C δ=0.5mm E = 200000 MPa △T=80°C and σy=0

Answered: mperature. The temperature of the bar…

mperature. The temperature of the bar is increased uniformly by 80 c°. etermine the average axial stress and change in the diameter of the bar 1:

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The solid 1.25-in.-diameter rod is subjected to a uniform axial distributed loading along its length of w = 700 lb/ft. Two concentrated loads also act on the rod: P = 2100 lb and Q = 600 lb. Assume a = 12 in. andb= 24 in. Determine the normal stress in the rod at the following locations: (a) x = 8 in. (b) x = 24 in. w -> A C a b Answer: Ox-8in. = i psi Ox-24in. = i psi
Cylinder of height 2H. radius R. centroid at (0,0.H), axis e3 undergoes deformation x = o(z) = z + 23e3. Assuming stress-strain relation: S = aE, where a is a constant, total force on the base of the cylinder with normal -e3 is f = -1.5anR2 He3 total force on the base of the cylinder with normal - ez is f = 1.5aπR²e3 total force on the base of the cylinder with normal - ez is f = 1.5an R²Hez total force on the base of the cylinder with normal - ez is f = -1.5anR²e3
HW. 9-3. The state of stress at a point in a member is shown on the element. Determine the stress components acting on the inclined plane AB. Solve the problem using the method of equilibrium described in Sec. 9.1. 60 400 psi *650 pகம்
The cross sectional area of the bar ABCD is 550 mm2. F1 = 25 kN, F2 = 20 kN, F3 = 35 kN. F1 F2 F3 Be C D +-1.5 m-+ 3 m- 3 m a. Determine the normal stress in bar AB. Specify whether tension or compression. b. Determine the normal stress in bar BC. Specify whether tension or compression. c. Determine the normal stress in bar CD. Specify whether tension or compression. d. Determine the maximum normal stress in the bar. Specify whether tension or compression.
The d = 16-mm-diameter solid rod passes through a D = 21-mm-diameter hole in the support plate. When a load P is applied to the rod, the rod head rests on the support plate. The support plate has a thickness of b = 11 mm. The rod head has a diameter of a = 32 mm, and the head has a thickness of t = 10 mm. The shear stress in the rod head cannot exceed 130 MPa, the punching shear stress in the support plate cannot exceed 90 MPa, and the bearing stress between the rod head and the support plate cannot exceed 145 MPa. Determine the maximum value of Pmax that can be supported by the structure. P Support Plate Rod Answer: Pmax i Hole diameter D Head KN
Determine the maximum stress of the plate. rivet hole diameter= 2 cm • width of the plate= 6 cm • uni-axial tension of 55 MPa.
1.1 Two solid cylindrical rods AB and BC are welded together at B and loaded as shown. Knowing that d₁ = 30 mm and d₂ = 50 mm, find the average normal stress at the midsection of (a) rod AB, (b) rod BC. d₂ 125 kN B 60 kN 125 kN 1.2 m 0,9 m
Find max and min stresses. Please provide step by step solution. Don't copy!!
The solid 1.55-in.-diameter rod is subjected to a uniform axial distributed loading along its length of w = 775 lb/ft. Two concentrated loads also act on the rod: P = 1700 Ib and Q = 600 lb. Assume a = 12 in. and b = 24 in. Determine the normal stress in the rod at the following locations: (a) x= 8 in. (b) x = 24 in. → - A В IC a Answer: Ox-8in. - psi Ox-24in. psi
All forces applied in the system are in the (x - y) plane. The material point B at the top of the beam is rotated at an angle of 15° counterclockwise. It is required that the shear stress is 17.5 MPa for this rotated material point B. At the bottom point A of the beam it is required that the maximum tensile stress is 110 MPa. Determine the load P and the length d that satisfies these constraints defined for points A and B. Given data: L= 4 b, t = b / 25, c = 2b, b = 1000 mm, e = 12, f=5 b/4- q = 2P/L b/ 4 -b/4- P
Determine the maximum stress of the plate. rivet hole diameter= 2 cm • width of the plate= 6 cm • uni-axial tension of 55 MPa.
g44. The tapered member is fixed connected at its ends A and Band is subjected to a load P.Determine the location x of the load and its greatest magnitude so that the average normal stress in the har does not exceed oa = 28 MPa. The member is 50 mm thick. 150 - 1500 mm