Medical practitioners are increasingly utilising the Zoom platform. Not only for online meetings but also for consultations with patients. The weekly Zoom access time (in hours) at two hospitals:Health Care I Health Care II needs to be investigated.Given: The weekly access time of medical practitioners at both hospitals is normally distributed with a standard deviation of σ=5 hours.please answer b)Consider the weekly access time at Health Care IIThe Superintendent wants to investigate the average weekly access time (in hours) at Health Care II based on 2 different researchquestions. A random sample of the weekly access times of n30 medical practitioners revealed an average of = 21.05 hours.Let: 4= mean weekly access time of the medical practitioners.Research Question 1: Is the mean weekly access time less than 22 hours?Given: The value of the test statistic isz = -1.04Complete the following:Identify the correct null hypothesis:O Ho: < 21.05O Ho µ + 22O Ho: µ < 21.05O Ho: u = 22Ho 21.05O Ho : µ # 21.05O Ho 22O Ho > 22O Ho: > 22O Ho: = 21.05O Ho: µ = 21.05O Ho u < 220.O Ho: = 22O Ho: > 21.05O Ho: µ > 21.05O Ho: < 22 Research Question 2: Does the mean weekly access time differ from 21 hours?Given: The 90% confidence interval for µ is:(19.5 , 22.6)Complete the following;• According to the observed confidence interval, the null hypothesis isand there is sufficient evidence to claim thatthe average access timev from 21 hours, at 0.1 level of significance.According to the observed confidence interval, we know that:True False90% of all samples should have sample means between 19.5 and 22.6.We are 90% confident that µ is between 19.5 and 22.6.For every 100 random samples drawn, we expect that 90 of the confidence intervals willcontain the population mean.The probability that µ is between 19.5 and 22.6 is 0.9.90% of all medical practitioners at Health Care Il have access times between 19.5 and 22.6hours.For every 100 random samples drawn, we expect that 90 of the confidence intervals willcontain the sample mean.$31 PM

Given : z value = -1.04 x = 21.05μ = 22n = 30σ = 5

Answered: Medical practitioners are increasingly…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

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Question

Medical practitioners are increasingly utilising the Zoom platform. Not only for online meetings but also for consultations with patients. The weekly Zoom access time (in hours) at two hospitals:

Health Care I
Health Care II

needs to be investigated.

Given: The weekly access time of medical practitioners at both hospitals is normally distributed with a standard deviation of σ=5 hours.

please answer

b)
Consider the weekly access time at Health Care II
The Superintendent wants to investigate the average weekly access time (in hours) at Health Care II based on 2 different research
questions. A random sample of the weekly access times of n
30 medical practitioners revealed an average of = 21.05 hours.
Let: 4
= mean weekly access time of the medical practitioners.
Research Question 1: Is the mean weekly access time less than 22 hours?
Given: The value of the test statistic is
z = -1.04
Complete the following:
Identify the correct null hypothesis:
O Ho: < 21.05
O Ho µ + 22
O Ho: µ < 21.05
O Ho: u = 22
Ho 21.05
O Ho : µ # 21.05
O Ho 22
O Ho > 22
O Ho: > 22
O Ho: = 21.05
O Ho: µ = 21.05
O Ho u < 22
0.
O Ho: = 22
O Ho: > 21.05
O Ho: µ > 21.05
O Ho: < 22

Research Question 2: Does the mean weekly access time differ from 21 hours?
Given: The 90% confidence interval for µ is:
(19.5 , 22.6)
Complete the following;
• According to the observed confidence interval, the null hypothesis is
and there is sufficient evidence to claim that
the average access time
v from 21 hours, at 0.1 level of significance.
According to the observed confidence interval, we know that:
True False
90% of all samples should have sample means between 19.5 and 22.6.
We are 90% confident that µ is between 19.5 and 22.6.
For every 100 random samples drawn, we expect that 90 of the confidence intervals will
contain the population mean.
The probability that µ is between 19.5 and 22.6 is 0.9.
90% of all medical practitioners at Health Care Il have access times between 19.5 and 22.6
hours.
For every 100 random samples drawn, we expect that 90 of the confidence intervals will
contain the sample mean.
$31 PM

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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