PRINTER VERSION1 BACKNEXTChapter 11, Problem 022Your answer is partially correct. Try again.A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector = (2.00 m) i - (3.00 m) j + (2.00 m) k,the force is F = F, i + (7.00 N) j - (6.00 N) k, and the corresponding torque about the origin is 7 = (4.00 N-m) i + (10.0 N-m)j + (11.0 N-m) k. Determine FNumberUnitsthe tolerance is +/-2%Click if you would like to Show Work for this question: Open Show WorkQuestion Attempts: UnlimitedSAVE FOR LATERSUBMIT ANSWERm

→r=2i - 3j +2k→F=FXi +7j -6k→ζ=4i+10j+11k

m) î - (3.00 m)} + (2.00 m) k, the force is F = F,i + (7.00 N)} - (6.00 N) k, and the corresponding torque about the origin is 7 = (4.00 N-m) i + (10.0 N-m) j + (11.0 N-m) k. Determine F A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector r = (2. Number "

m) î - (3.00 m)} + (2.00 m) k, the force is F = F,i + (7.00 N)} - (6.00 N) k, and the corresponding torque about the origin is 7 = (4.00 N-m) i + (10.0 N-m) j + (11.0 N-m) k. Determine F A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector r = (2. Number "

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector r→ = (2.00 m) î - (3.00 m) ĵ + (2.00 m) k̂, the force is F→ = Fx î + (7.00 N) ĵ - (6.00 N) k̂, and the corresponding torque about the origin is τ→ = (4.00 N·m) î + (6.00 N·m) ĵ + (5.00 N·m) k̂. Determine Fx.