lons that react with Ag like SCN can be determined electrogravimetricallyby deposition on a silver working anode:(c)Ag(s) + SCN AGSCN(s) + eA silver anode with initial mass of 12.4730 g was used to electrolyse 85.00 mL of asolution of 0.0245 M KSCN. At the end of the experiment, the anode weighed12.5767 g. How long did the experiment take, if a current of 100 mA was used?

A numerical problem based on electrochemistry, which is to be accomplished.

Answered: lons that react with Ag like SCN can be…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Using the provided reduction half-reactions, which of the following materials can be used to oxidize Cu without oxidizing Ag? Show your work to justify your answer. Reduction Half-Reaction E°red V F2(g) + 2e¯→ 2 F(aq) +2.87 O2(s) + 4 H*, 10, (aq) + 6 H*+ 5e→ %l,{s) + 3H,0(1) + 4 e → 2 H,0(ag) +1.23 (aq) +1.20 Ag*(aq) + 1e→ Ag(s) +0.80 ,(s) + 2e→ 21-(aq) +0.54 Cu2*(aq) + 2e-→ Cu(s) +0.34 Pb2+ {aq) + 2 e-→ Pb(s) -0.13 Cr3*(aq) + 1e→ Cr2*(aq) -0.50 Mg2*(aq) + 2e-→ Mg(s) -2.37
Pt(s) IX*(ag), X2+, ELECTROCHEMISTRY: (aq) | Y(s) Given the line notation: (aq) || y3+ where: x2+ + e - x+ E° = 0.94 V y3+ + 3 e → Y E° = -2.71 V Pt4+ + 4 e E° = 1.20 V Pt Calculate the EMF.
A concentration cell composed of Cus)|Cu2* (aq, 0.10M)||Cu2* obtained. The cell was left sitting for a few minutes. (aq, 1.0M)|Cu(s) is connected to a voltmeter. Initially a reading of 29.6 mV was How has the voltage change compared to the initial reading? Why did this change occur?
The reduction potential to the metal of Ba 2+ is -1.57 V and that of Cu 2+ is +0.34 V. The cell potential for the reaction Ba(s) + Cu 2+ (aq) → Ba 2+ (aq) + Cu(s) is therefore: a. (+1.57) + (+0.34) b. (+1.57) + (-0.34) c. (-1.57) + (+0.34) d. 2 x (-1.57) + 2 x (0.34) e. (-1.57) + (0.34)
Chromium can be electroplated from aqueous potassium dichromate, with the reduction shown below. If a current of 5 A and a voltage of 4.5V are used: Cr20, (aq) + 14H+ (aq)+ 12e¯ → 2Cr(s) + 7H20 How many hours would it take to completely convert 215 mL of 1.11 M K2Cr207 to elemental chromium?
Tin was immersed in a CuCl2 solution with activity Cu2+= 0.2. Calculate the Sn 2+ concentration when corrosion stops
A solution prepared by mixing 60.0 mL of 0.360 M AGNO, and 60.0 mL of 0.360 M TINO, was titrated with 0.720 M NaBr in a cell containing a silver indicator electrode and a reference electrode with a constant potential of 0.175 V. The reference electrode is attached to the positive terminal of the potentiometer, and the silver electrode is attached to the negative terminal. The solubility constant of TIBr is Kp = 3.6 × 10-6 and the solubility constant of AgBr is = 5.0 x 10-13. Ksp Which precipitate forms first? O TIBI O AgBr Which of the expressions shows how the cell potential, E, depends on [Ag*]? E = 0.175 V – [0.799 V – 0.05916log ([Ag+])] 1 E = |0.799 V – 0.05916log - 0.175 V [Ag*) E = [0.799 V – 0.05916log ([Ag*]D] – 0.175 V E = 0.175 V - |0.799 V – 0.05916log [Ag* * (ল) Calculate the first and second equivalence points of the titration. first equivalence point: mL second equivalence point: mL What is the cell potential after each of the given volumes of 0.720 M NaBr have been…
Complete this table relating the values of Eu and AG° to K. 'cell K AG 'cell Answer Bank 0 = 0 1 V
A solution containing Pt4t is electrolyzed with a current of 4.30 A. How long will it take to plate out 99% of the platinum in 0.55 L of a 0.030-M solution of Pt4+? Time =
6. Suppose you wish to separate Cd²+ from Zn²+ by electrodeposition of metallic cadmium onto an inert cathode from an aqueous solution containing 0.015 M Cd(NH3)4²+, 0.010 M Zn(NH3)4²+, and 1.00 M uncomplexed NH3. You want to deposit 99.99% of the Cd while not depositing any Zn. What is the allowable range of potentials that you can use? Cd(NH3)4²+ + 2e = Cd(s) + 4 NH3 Zn(NH3)4²+ + 2e → Zn(s) + 4 NH3 E = -0.61 V vs. SHE E° -1.04 V vs. SHE
Find the theoretical cell potential for each
Balance the following reaction in basic solution. Ag(s) + Zn²+(aq) → Ag,O(ag) + Zn(s) Fill in the coefficients and substances for the balanced overall equation. Note: Do NOT leave any coeffient fields empty. If the coefficient is 1, choose "1" as opposed to leaving it blank. -- v Ag + -- v Zn2+ + v Zn + Ag,0 + -- v--

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