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last two digit number is: 01

last two digit number is: 01

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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last two digit number is: 01

 

Q2 The A kg collar is initially at rest on the bar at position 1 as shown in Figure Q2. The coefficient of friction between collar and the bar is given as u = 0.1. The collar is subjected to a constant force P = 50 N horizontally. The spring has a constant k = 150 N/m and is held by cables so that it is initially compressed B em. Suppose the spring will be compressed 100 mm further when the collar hit the spring at position 2. Here, the value of A and B depends on the 5th and 6th digit of your matric number respectively as shown in Table 1. For example, if your matric number is DD 170150 gives the value of A = 5 kg and B = 10 cm. Table 1 5th digit of 6th digit of matrix number A B matric number 10 10 1 1 1 1 2 2 2 3 3 3 3 4 4 4 4 5 5 5 5 7 7 7 7 8 8 8 8 9 9 9 (a) Sketch the free body diagram ofcollar at position 1.
Transcribed Image Text:Q2 The A kg collar is initially at rest on the bar at position 1 as shown in Figure Q2. The coefficient of friction between collar and the bar is given as u = 0.1. The collar is subjected to a constant force P = 50 N horizontally. The spring has a constant k = 150 N/m and is held by cables so that it is initially compressed B em. Suppose the spring will be compressed 100 mm further when the collar hit the spring at position 2. Here, the value of A and B depends on the 5th and 6th digit of your matric number respectively as shown in Table 1. For example, if your matric number is DD 170150 gives the value of A = 5 kg and B = 10 cm. Table 1 5th digit of 6th digit of matrix number A B matric number 10 10 1 1 1 1 2 2 2 3 3 3 3 4 4 4 4 5 5 5 5 7 7 7 7 8 8 8 8 9 9 9 (a) Sketch the free body diagram ofcollar at position 1.
k = 150 N/m 50 cm P = 50 N Www 2 A kg 110 cm 30° p = 0.1 ww MW A kg Figure Q2
Transcribed Image Text:k = 150 N/m 50 cm P = 50 N Www 2 A kg 110 cm 30° p = 0.1 ww MW A kg Figure Q2
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