Initial Kinetic Energy, Ko Final Kinetic Energy,Kf Velocity, v Calculations: m = 150 kg k = 1000 N/m x = 0.8 m At = 8.72 s Ax = 18 m For computed velocity: Vc=|Axt| Vc=18 m8.72 s=2.0642 m/s For Initial Elastic Potential Energy: For Velocity: For Final Kinetic Energy: For Percentage Error: Observations/Interpretation:

Initial Kinetic Energy, Ko Final Kinetic Energy,Kf Velocity, v Calculations: m = 150 kg k = 1000 N/m x = 0.8 m At = 8.72 s Ax = 18 m For computed velocity: Vc=|Axt| Vc=18 m8.72 s=2.0642 m/s For Initial Elastic Potential Energy: For Velocity: For Final Kinetic Energy: For Percentage Error: Observations/Interpretation:

Name: Initial Kinetic Energy,KoFinal Kinetic Energy,KfVelocity, vCalculatio
Uploaded: 2024-03-20T06:57:25.000Z
Channel: Bartleby
Description: Initial Kinetic Energy,KoFinal Kinetic Energy,KfVelocity, vCalculations:m = 150 kgk = 1000 N/mx = 0.8 mAt = 8.72 sAx = 18 mFor computed velocity:Vc=|Ax^t|Vc 18 m8.72 s=2.0642 m/sFor Initial Elastic Potential Energy:For Velocity:For Final Kinetic Ene

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

The above graph shows the potential energy U(x) of a particle as a function of its position x. The total mechanical energy in the system is marked with the dashed horizontal line at 4 Joules. what is the Inventory Initial Energy of this problem? Describe Energy in System at First Critical PointUse Relevant Formats and Tools to Communicate Initial Energy State
In the figure shown, if the mass (m=4 Kg) is moving with constant speed and traveled a distance d317 m, what is the work done in Joules by frictional force? Given that F =15 N and e =53 °. A. None B. -306.9 C. -153.5 D. -460,4 E. -613.8
Find the work done in joules by gravity as an object of the mass m=15 kg is raised up at constant speed from a height h1=35 m to a height h2-69 m. Consider g = 10 m/s² A. -15300 B. None C. -5100 D. -2550 E. -10200 O < O o OUOD
9. From the second law of motion and the equation for velocity EF=ma Derive the Work - Energy equation: = 1 + 2a(x₂-x1) W = K₂-K₁
Conservation of Energy Calculate K, U, E for: = 500kg A = 100⁰m B = 50~ m m 700 c=0m D=50m E = 75m V=0₂V= 10 m/s 50 A 12 75- B Por K = kinetic energy U = potential energy E = total mechanical energy o
RELATIONSHIP BETWEEN WORK AND ENERGY Theory: The net work done on an object always produces a change in kinetic energy of the object. Vo P Total work done = AKE Positive work - Negative work = KEinal KEinitial P(S) - F(S) = -mv² -mvo2 21 1. %3D 2 12. What average force is required to stop a bullet of mass 20 grams and speed 250 m/ s as it penetrates wood to a distance of 12 cm?
Cart Mass, mc . 284 kg Angle, θ 49 degrees Distance, d . 75 m Equilibrium . 240 Velocity 1 . 664 m/s Velocity 2 . 672 m/s Velocity 3 .670 m/s Average Velocity .669 m/s What is the kinetic Energy ? Using the average velocity, calculate the cart's change in Kenetic Energy. KE = (1/2) mv2
QUESTION 6 A falling package with a parachute is greatly affected by air resistance. Suppose a package (m 25 kg), dropped from an altitude of y = 1500 m, hits the ground at a speed of v = 45 m/s. Calculate the work done by air resistance. By conservation of energy, the initial total mechanical energy is equal to the final total mechanical energy. Let K be the kinetic energy, U be the gravitational potential energy, and Wair be the work done by the drag force from air resistance.
TNT AR @N 19111:10 greater the gravitational potential energy. 12. A 50kg and 40kg man climbed a coconut tree with a height of 15m. Compare the potential energy of each man. A. The potential energy of each man is 7,350J and 5,880J. B. The potential energy of a 50kg man is 7,350J that is greater compared to a 5,880J potential energy of a 40kg man. C. The potential energy of 50kg and 40kg man who climbed a height of 15m are 7,350J and 5,880J respectively. D. The potential energy of a 50kg man is 7,350J that is greater compared to a 5,880J potential energy of a 40kg man thus the greater the mass of a body the greater the potential energy. 13. What is kinetic energy? A. Kinetic energy is the energy in motion. B. Kinetic Energy is the energy possessed by a moving object. C. Kinetic energy is the energy in motion, and it is expressed in Joule. D. Kinetic energy is the energy in motion, and it depends on the mass and velocity of the object. 14. Two cars A and B are travelling at a velocity of…
Potential Energy
1. A roller-coaster car with a mass of 1200 kg starts at rest from a point 20 m above the ground. At point B, it is 9 m above the ground. [Express your answers in kilojoules (kJ).] a. What is the initial potential energy of the car? b. What is the potential energy at point B? c. If the initial kinetic energy was zero and the work done against friction between the starting point and point B is 40 000 J (40 kJ), what is the kinetic energy of the car at point B 2. The time required for one complete cycle of a mass oscillating at the end of a spring is 0.80 s. What is the frequency of oscillation?
QUESTION 9 While moving a package up and down on a storage shelf the mover does +500 J of work and gravity does-500 J of work. Which statement is true about the Potential Energy and the Kinetic Energy of the package: A. The Potential Energy of the package is decreased. B. The Potential Energy of the package is increased. C. The Kinetic Energy of the package is increased. D. The Kinetic Energy of the package is decreased. E, The Potential Energy of the package does not change.