In a study of factors affecting hypnotism, visual analogue scale (VAS) sensory ratings were obtained for 16 subjects. For these sample ratings, the mean is 8.33 with a standard deviation of 2.06. At a=0.05 level of significance test the claim that this sample comes from a population with a mean rating of less than 10.00.
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- Researchers from a certain country were interested in how characteristics of the spleen of residents in their tropical environment compare to those found elsewhere in the world. The researchers randomly sampled 93 males and 107 females in their country. The mean and standard deviation of the spleen lengths for the males were 10.8 cm and 0.9 cm, respectively, and those for the females were 10.2 cm and 0.7 cm, respectively. At the 5% significance level, do the data provide sufficient evidence to conclude that a difference exists in the mean spleen lengths of males and females in the country? Click here to view page 1 of the table of critical values of t. Click here to view page 2 of the table of critical values of t. O E. Ho: H1 H₂ Hai Hg = H2 Compute the test statistic. =(Round to two decimal places as needed.) Determine the critical value(s). t= OF. Ho: H1 H₂ Ha: H1 H₂ 0 (Round to three decimal places as needed. Use a comma to separate answers as needed.) What is the conclusion of the…1) A study compared the weight loss of people on a low-fat diet versus people on a low-carb diet. In a sample of 100 obese people on a low-fat diet the sample mean weight loss as 7.6 pounds with a standard deviation of 3.2 pounds. In another sample of 120 obese people on a low-carb diet the sample mean weight loss was 6.7 pounds with a standard deviation of 3.9 pounds. a) Test the hypothesis, at the 5% level of significance, that there is a difference in the mean weight loss of using the 2 different diets. b) What is the p-value?In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with raw garlic Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.1 and a standard deviation of 23.2. Use a 0.01 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? O A. Ho p=0 mg/dL O B. H, p=0mg/dL H, p0 mg/dL OC. Ho H>0 mg/dL O D. H, p=0 mg/dL. H, pz0 mg/dL. H, p<0 mg/dL
- You were told that the mean daily cost of a hotel room in downtown St. Louis is $120. You will be needing to rent a hotel room there in the near future and you want to find the best rate. You randomly select a sample of 18 hotel rooms and find that the average cost is $121.33 with a standard deviation of $18.046. At the α = 0.05 significance level, determine if there is enough evidence to reject the claim. What is the decision for this hypothesis test? You were told that the mean daily cost of a hotel room in downtown St. Louis is $120. You will be needing to rent a hotel room there in the near future and you want to find the best rate. You randomly select a sample of 18 hotel rooms and find that the average cost is $121.33 with a standard deviation of $18.046. At the α = 0.05 significance level, determine if there is enough evidence to reject the claim. What is the decision for this hypothesis test? Reject the null because the test statistic is in the critical region and the…Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of womenThe Ankle Brachial Index (ABI) compares the blood pressure of a patient's arm to the blood pressure of the patient's leg. A healthy ABI is 0.9 or greater. In a study, researchers obtained the ABI of 187 women with arterial disease. The results were a mean ABI of 0.86 with a standard deviation of 0.16. At the 1% significance level, do the data provide sufficient evidence to conclude that, on average, women with arterial disease have an unhealthy ABI? Set up the hypotheses for the one-mean t-test. Hou Ha: H
- A pharmaceutical company needs to know if its new cholesterol drug, Praxor, is effective at lowering cholesterol levels. It believes that people who take Praxor will average a greater decrease in cholesterol level than people taking a placebo. After the experiment is complete, the researchers find that the 4848 participants in the treatment group lowered their cholesterol levels by a mean of 21.521.5 points with a standard deviation of 2.52.5 points. The 4040 participants in the control group lowered their cholesterol levels by a mean of 20.920.9 points with a standard deviation of 4.14.1 points. Assume that the population variances are not equal and test the company’s claim at the 0.100.10 level. Let the treatment group be Population 1 and let the control group be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places. step 3 of 3 : Conclusion- fail to reject/reject...insufficient/sufficientIt is commonly believed that the mean body temperature of a healthy adult is 98.6°F. You are not entirely convinced. You believe that it is not 98.6° F. You collected data using 52 healthy people and found that they had a mean body temperature of 98.25° F with a standard deviation of 1.2° F. Use a 0.05 significance level to test the claim that the mean body temperature of a healthy adult is not 98.6°F. a) kdentify the null and alternative hypotheses? Họ:p=v 98.6 H.: pIn a test of the effectiveness of garlic for lowering cholesterol, 4949 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.30.3 and a standard deviation of 2.142.14 Use a 0.100.10 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 00. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? A. Upper H 0H0: muμequals=00 mg/dL Upper H 1H1: muμless than<00 mg/dL B. Upper H 0H0: muμequals=00 mg/dL Upper H 1H1: muμgreater than>00 mg/dL C. Upper H 0H0: muμequals=00 mg/dL Upper…In a test of the effectiveness of garlic for lowering cholesterol, 4949 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.40.4 and a standard deviation of 23.823.8. Use a 0.010.01 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 00. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Determine the test statistic. nothing (Round to two decimal places as needed.)A pharmaceutical company claims that its new drug is effective in reducing blood pressure with a mean reduction of at least 5 mmHg. To test this claim, a random sample of 30 patients is selected and given the medication. The results show an average reduction in blood pressure of 4.7 mmHg with a standard deviation of 1.2 mmHg. Test the company's claim at a 5% significance level.. In a study of factors affecting hypnotism, visual analogue scale (VAS) sensory ratings were obtained for 16 subjects. For thesesample ratings, the mean is 8.33 while the standard deviation is 1.96 (based on data from “An Analysis of Factors ThatContribute to the Efficacy of Hypnotic Analgesia,” by Price and Barber, Journal of Abnormal Psychology, Vol. 96, No. 1). At0.01 level of significance, test the claim that this sample comes from a population with a mean VAS rating of less than 10.00.a. Claim (in symbolic form): __________b. Ho:Ha:c. level of significance: test-statistic: _____ tail of distribution: ______d.Decision Rule: Reject Ho if ______________e. Computation