Answered: In a roasting plant, 1000 kg per hour…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Question

The major objective of a roasting process is to eliminate the Sulphur contained in the concentrate and
to provide a calcine. In a roasting plant, 1000 kg per hour of molybdenum(IV) sulphide (MoS2) is roasted
with 25 % excess air to obtain MoO3 calcine in a chamber-type roasting furnace. Preheated air enters
the reactor at 400 K while MoS2 enters at room temperature. After the process, the waste gases leave
the reactor at 1000 K, and the calcine leaves at 850 K.

d) Calculate the heat of reaction per hour (in kJ) of roasting of 1000 kg MoS2 (ref. 298 K)
e) Calculate the heat per hour (in kJ) which is lost to the surrounding.

Supplemental:
Mo=95.95 g/mol
S= 32.06 g/mol
O=16 g/mol
N=14 g/mol
AHMos2,298K = -276.14 kj/mol
AHMO03,298K = -745.1 kj/mol
AHsozle),298K = -296.8 kj/mol
Mean value of Cp 02 = 30.10 J/mol*K
Mean value of Cp n2 = 29.05 J/mol*K
[H°so K - H°298 K]Mo03 = 20.24 kJ/mol
Mean value of Cp so2 = 47 J/mol*K
SO2

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